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Sindrei [870]
2 years ago
14

As the train in the image moves to the right how does the train horn sound to person a?

Physics
2 answers:
MissTica2 years ago
4 0

Answer:

D. The pitch does not change.

Explanation:

When the source of sound moves away, the pitch drops. and when the source of sound approaches the pitch rises. This is called'Doppler effect'.

Here the person a and the sound horn are both in the same vehicle. Which means their relative velocity is zero. So the horn is neither approaching nor receding the person A

If  the source is approaching

f_{new}= \frac{v_{sound} }{v_{sound} -v_{source} }f_{original}

If the source is receding

f_{new}= \frac{v_{sound} }{v_{sound} +v_{source} }f_{original}

Hence the right answer is option D. The pitch does not change

alina1380 [7]2 years ago
3 0

Answer:

Explanation:

Person A's velocity relative to the train is 0.  Therefore, the pitch of the horn will not change.

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You push on a box with a force of 300 N directly north. Another person pushes the box with a
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If 2 objects have the same momentum which statement is true
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Read 2 more answers
An oscillator consists of a block of mass 0.628 kg connected to a spring. When set into oscillation with amplitude 27 cm, the os
oksian1 [2.3K]

Answer:

T=0.372 s, f=2.7 Hz, w=16.9 rad/s, k=179.2 N/m, v= 8.78 m/s, F= 48.4 N

Explanation:

a.)

Period: It is already given in the question "oscillator repeats its motion every 0.372 s".

So T=0.372 s

b)

frequency= f = 1/ T

f = 1/ 0.372

f=2.7 Hz

c).

Angular frequency= w= 2πf

w= 2*π*2.7

w=16.9 rad/s

d)

Spring Constant:

As w=\sqrt{k/m}

⇒w²= k/m

⇒k= m*w²

⇒k= 0.628 * 16.9² N/m

⇒k=179.2 N/m

e)

The mass will have maximum speed when it passes through the mean position.

At mean position

Maximum elastic potential energy = Maximum kinetic energy

1/2 k A² = 1/2 m v²    ( A is amplitude of oscillation)

⇒ v=\sqrt{k A^2/m}

⇒ v= \sqrt{179.2 * 0.27/ 0.628}\

⇒ v= 8.78 m/s

f)

Maximum force will be exerted on the block when it is at maximum distance.

F= k* A   ( A is amplitude of oscillation)

F= 179.2 * 0.27 N

F= 48.4 N

5 0
3 years ago
A lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms , what is the average
malfutka [58]

The average electric current in the lightning will be 8 × 10^{-17} A

<h3>Why Lightning Conductors on top of a tower ?</h3>

The lightning conductors are long metal strips running from the spike end of a conductor on the top of a building to the earth. They are used to prevent buildings from destruction when struck by thunder or lightning.

Given that a lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms, to calculate the average electric current in the lightning, we will first consider the charge released.

one charge = 1.6 × 10^{-19} C

Average current I = Q/t

Where

  • Q = charge = 1.6 × 10^{-19} C
  • t = time = 2ms = 2 × 10^{-3} s
  • I = current = ?

Substitute all the parameters into the formula

I = 1.6 × 10^{-19} C ÷ 2 × 10^{-3}

I = 8 × 10^{-17} A

Therefore, the average electric current in the lightning will be 8 × 10^{-17} A

Learn more about Lightning here: brainly.com/question/3183045

#SPJ1

5 0
2 years ago
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