Answer:
Substitute -8 as x into the equation.
h(-8)=-2(-8+5)^2+4
h(-8)=-2(-3)^2+4
h(-8)=-2(9)+4
h(-8)=-18+4
h(-8)=-14
:)
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
Answer:
Step-by-step explanation:
x 0 , VCB ln(1 4x2 ) tương đương với
Answer
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This would be 21.5π * 360 / 20 yd^2 = 1215.18 yd^2 ( using pi = 3.14)
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Hello from MrBillDoesMath!
Answer:
r = C/6.28
Discussion:
Note that C = 2 * Pi * r is the exact formula. As Pi is approximately 3.14, the given formula, C = 2 (3.14) r, is an approximation. Solving it for r:
C = 2(3.14) r => as 2 * 3.14 = 6.28
C = 6.28 r => divide both sides by 6.28
r ( 6.28/6.28) = C/6.28 => as 6.28/6.28 = 1
r = C/6.28
Thank you,
MrB
