Answer:
Kc = 1.54e - 31 / 2.61e - 24
Explanation:
1 )
; Kc = 1.54e - 31
2)
; Kc = 2.16e - 24
upon reversing ( 2 ) equation
Kc = 1/2.16e - 24
now adding 1 and reversed equation (2)


we get ,
Kc = 1.54e-31 × 1/2.61e - 24
equilibrium constant of equation (3) is -
Kc = 1.54e - 31 / 2.61e - 24
Technically there is only one phase unless you account for a solution where you have a pure liquid with something dissolved in it. Unless you count aqueous as a phase which is just dissolved. Since you are in high school the answer you are looking for is one. <span />
Answer:
The death is lower
Explanation:
im gonna get a warning watch
60 g C2H6 × 1 mol C2H6 x 7 mol O2 x 32 g O2 = ~223.5 g O2
30.068 g 2 mol C2H6 1 mol O2
The mass percent of each compound is
- (NaBr*2H2O)=85.71 percent
- (MgBr2*6H2O)=14.29 percent
<h3>The mass percent equation is as follows.</h3>
The formula mass percent is the most effective way to express mass percent: mass percent = (mass of chemical x total mass of compound) times 100. Add 100 to the top value to get the value expressed as a percentage.
<h3>What percentage by mass does a solution have?</h3>
By multiply the grams of solute per gram of solution by 100, it is possible to get the mass percent of a solution.
The molar mass of each element and the mass of each element contained in a mole of the compound are both solved for in the Mass Percent formula.
Learn more about Mass Percent here
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