You are offered two jobs. One with a yearly salary of $51,592, and the other an hourly

Mathematics

1 answer:

Crazy boy [7]3 years ago

4 0

You will make 11588 mor dollars for the hourly job

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Plz guys help i need asap<br> its part b im stuck

aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

1st quarter-2
2nd quarter-9
3rd quarter-7
4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

$\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8$

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

$g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4$

Hence, there are 4 more home goals than away goals.

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3 years ago

. Determine whether the vectors (5, −2, 4), (2, −3, 5), and (4, 5−

Tems11 [23]

Answer: The vectors are linearly dependent.

The solution is in the attachment

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3 years ago

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Looking for some furniture for her new apartment, Susan visits the local swap meet in search of something cheap. Knowing that mo

liraira [26]

Using the formula for interest:

F = P (1 + r/n)^t

Where:
F = future value
P = Principal value
r = interest rate per year
n = interest period
t = duration

Substituting the given values:
F = 200 (1 + 0.32/12)^1
F = 205.33

To obtain the interest, we subtract the principal value from the future value. This is shown below:

Interest = 205.33 - 200 = 5.33

Among the choices, the answer is A.

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2 years ago

Say True or false 1.all relations are functions ?

Elena L [17]

Answer is false, because every function is a relation but every relation is not a function :) (Please mark me brainliest)