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Bumek [7]
2 years ago
10

A peanut company ships its product in a carton that weighs 20 oz when empty. Twenty bays ul

Mathematics
1 answer:
Otrada [13]2 years ago
8 0

The compound inequality statement for the weight of cartons that would be inspected is 630 > X > 690

Weight of empty carton = 20 oz

Acceptable range of weight per bag of peanut :

  • Lower limit = 30.5 oz
  • Upper limit = 33.5 oz

Number of peanut bags per carton = 20 bags

Therefore,

The lower limit for weight of carton after being filled will be :

  • Weight of empty carton + (20 × weight per bag)
  • 20 + (20 × 30.5) = 630 oz

The Upper limit for weight of carton after being filled will be :

  • Weight of empty carton + (20 × weight per bag)
  • 20 + (20 × 33.5) = 690 oz

Therefore, the compound inequality for the cartons that will be inspected is : 630 > X > 690

Learn more :brainly.com/question/15748955

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17 __ a solution od d - 6 = 23<br><br> is it or is it not
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Solve the equation. StartFraction dy Over dx EndFraction equals5 x Superscript 4 Baseline (1 plus y squared )Superscript three h
dangina [55]

Answer:

Step-by-step explanation:

To solve the differential equation

dy/dx = 5x^4(1 + y²)^(3/2)

First, separate the variables

dy/(1 + y²)^(3/2) = 5x^4 dx

Now, integrate both sides

To integrate dy/(1 + y²)^(3/2), use the substitution y = tan(u)

dy = (1/cos²u)du

So,

dy/(1 + y²)^(3/2) = [(1/cos²u)/(1 + tan²u)^(3/2)]du

= (1/cos²u)/(1 + (sin²u/cos²u))^(3/2)

Because cos²u + sin²u = 1 (Trigonometric identity),

The equation becomes

[1/(1/cos²u)^(3/2) × 1/cos²u] du

= cos³u/cos²u

= cosu

Integral of cosu = sinu

But y = tanu

Therefore u = arctany

We then have

cos(arctany) = y/√(1 + y²)

Now, the integral of the equation

dy/(1 + y²)^(3/2) = 5x^4 dx

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y/√(1 + y²) = x^5 + C

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y - (x^5 + C)√(1 + y²) = 0

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5 0
3 years ago
Please help me in the question of commission ! Grade - 9 . ​
AlladinOne [14]

Answer:

Step-by-step explanation:

Commission for  amount  Rs. 5,00,00 = \frac{2}{100}*500000

                                                               = 2* 5000

                                                               = Rs. 10,000

total commission = Rs. 32,000

Remaining commission = 32500 - 10000

                                      = Rs. 22500

Let remaining amount of the restaurant = Rs. x

Commission on Rs. x = 22500

3% of x = 22500

\frac{3}{100}*x=22500\\\\x=22500*\frac{100}{3}\\\\x = 7500*100

x = Rs. 750000

Price of the restaurant = 750000 + 500000

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7 0
2 years ago
In the year 1995, there were 1200 students at pine elementary school. In the year 2010 there were 1500 students. Find the rate o
AnnZ [28]

The rate of change from 1995 to 2010 is 20 students per year and the linear function that models the data will be: y=20x-38700

<em><u>Explanation</u></em>

In the year 1995, there were 1200 students and in the year 2010, there were 1500 students.

If x represents the year and y represents the number of students, then two points in form of (x,y) will be: (1995, 1200) and (2010, 1500)

So, the rate of change or slope = (change in value of y / change in value of x) =\frac{1500-1200}{2010-1995}= \frac{300}{15}=20

Now, plugging  slope(m) = 20 and first point (x_{1}, y_{1}) =(1995,1200)  into <u>point slope form of linear equation</u> y-y_{1} =m(x-x_{1}) , we will get.....

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4 0
3 years ago
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