Find the y value for point F such that DF and EF form a 1:3 ratio. E(2,4) D(-3,-3)
2 answers:
I drew the segment and used Pythagorean theorem to solve for its measure. The line formed is the hypotenuse of the imaginary right triangle.
Among the choices only -1.33 and -1.25 is a feasible choice. But I am leaning towards -1.25 as the y-value of point F based on my diagram. Please see attachment
Among the choices only -1.33 and -1.25 is a feasible choice. But I am leaning towards -1.25 as the y-value of point F based on my diagram. Please see attachment
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9514 1404 393
Answer:
see attached
Step-by-step explanation:
It isn't clear what is supposed to go in the various blanks. We have elected to identify the corresponding congruent parts, and name the congruent triangles. The postulate supporting the conclusion is also shown.
In most cases, corresponding parts are marked congruent. The exception is the vertical angles in figure 22.
Answer:
3
Step-by-step explanation:
Calculate the distance d using the distance formula
d =
with (x₁, y₁ ) = (5, 4) and (x₂, y₂ ) = (- 1, 1)
d =
=
=
=
= 3 ← exact value
≈ 6.71 ( to 2 dec. places )