The question is incomplete, the complete question is:
When aqueous solutions of NaCl and
are mixed, a solid forms. Determine the mass of solid formed when 140.7 mL of 0.1000 M NaCl is mixed with an excess of an aqueous solution of
<u>Answer:</u> The mass of lead chloride produced is 1.96 g
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
.....(1)
Given values:
Molarity of NaCl = 0.1000 M
Volume of the solution = 140.7 mL
Putting values in equation 1, we get:

The chemical equation for the reaction of NaCl and lead nitrate follows:

By the stoichiometry of the reaction:
If 2 moles of NaCl produces 1 mole of lead chloride
So, 0.01407 moles of NaCl will produce =
of lead chloride
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
......(2)
Molar mass of lead chloride = 278.1 g/mol
Plugging values in equation 2:

Hence, the mass of lead chloride produced is 1.96 g