Answer:
The mantel. I'm pretty sure.
Explanation:
Explanation:
If you have chipped or broken glassware then it is very important that you should take precaution yourself by conveying about it to your teacher and class mates.
By doing so you are making everybody aware to be cautious of the chipped or broken glassware.
Also, it is advised that you should dispose of it in the designated glass waste area.
Therefore, we can conclude that all actions that you should take if you have chipped or broken glassware as as follows.
- Dispose of it in the designated glass waste area.
Answer:
Physical change
Explanation:
Physical change -
It is the type of reversible change , where there is change in the state of the matter , is referred to as a physical change .
There is no chemical process involved during state change , i.e. , no new substance is formed .
Hence , from the given statement of the question, the correct term is physical change.
Answer:
(a) The system does work on the surroundings.
(b) The surroundings do work on the system.
(c) The system does work on the surroundings.
(d) No work is done.
Explanation:
The work (W) done in a chemical reaction can be calculated using the following expression:
W = -R.T.Δn(g)
where,
R is the ideal gas constant
T is the absolute temperature
Δn(g) is the difference between the gaseous moles of products and the gaseous moles of reactants
R and T are always positive.
- If Δn(g) > 0, W < 0, which means that the system does work on the surroundings.
- If Δn(g) < 0, W > 0, which means that the surroundings do work on the system.
- If Δn(g) = 0, W = 0, which means that no work is done.
<em>(a) Hg(l) ⇒ Hg(g)</em>
Δn(g) = 1 - 0 = 1. W < 0. The system does work on the surroundings.
<em>(b) 3 O₂(g) ⇒ 2 O₃(g)
</em>
Δn(g) = 2 - 3 = -1. W > 0. The surroundings do work on the system.
<em>(c) CuSO₄.5H₂O(s) ⇒ CuSO₄(s) + 5H₅O(g)
</em>
Δn(g) = 5 - 0 = 5. W < 0. The system does work on the surroundings.
<em>(d) H₂(g) + F₂(g) ⇒ 2 HF(g)</em>
Δn(g) = 2 - 2 = 0. W = 0. No work is done.
