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Sloan [31]
2 years ago
14

PLEASE ANSWER FAST I NEED HELP

Mathematics
2 answers:
just olya [345]2 years ago
6 0

Answer:

18 cubes

1/9

2/3

Step-by-step explanation:

Disclaimer: Im in 4th grade and i know this so my advice is get bett-

a) Count the cubes, so 18

b) Volume is s^3 so (1/3)^3 is 1/9 for one cube

c) Volume for large solid is h*w*l so ({1/3)*3} times ({1/3)*3} times (1/3*2)

you get 1*1*2/3

so 2/3

igomit [66]2 years ago
4 0

Answer:

18 cubes

1/9

2/3

Step-by-step explanation:

Disclaimer: Im in 4th grade and i know this so my advice is get bett-

a) Count the cubes, so 18

b) Volume is s^3 so (1/3)^3 is 1/9 for one cube

c) Volume for large solid is h*w*l so ({1/3)*3} times ({1/3)*3} times (1/3*2)

you get 1*1*2/3

so 2/3

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Ilia_Sergeevich [38]

Answer:

360 cm^2

Step-by-step explanation:

length x width x height

6 x 6 x 10

3 0
3 years ago
Read 2 more answers
A). A(n)= 46-n * (4-1)<br> B). A(n)= 46 - (n-1)*4<br> C). A(n)= 46 - 4^n-1<br> D). A(n)= 46 - 4^n+1
UkoKoshka [18]
I think it is answer C.
4 0
4 years ago
Find the condition that one root of the quadratic equation may be 1 more than the other.
Eddi Din [679]
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
4 0
4 years ago
A triangle has perimeter 59 cm. The lengths of the sides are 2x – 5 cm, 3x + 2 cm and 2x – 1 cm.
Dennis_Churaev [7]

Answer:2x - 5cm + 3x +2cm + 2x - 1cm=59cm

2x + 3x + 2x + 2cm + 1cm - 5cm=59cm

7x - 2cm=59cm

7x - 2cm + 2cm=59cm + 2cm

7x=61cm

X=8 5/7cm

Step-by-step explanation:

4 0
3 years ago
Segment AB has endpoints at A(-7,2) and b(9,-6). Point P lies on AB such that AP:BP=3:1
bekas [8.4K]

The coordinates of the point P which divides the line segment AB made by the points A(-7,2) and B(9,-6) is  (x,y) = (5,-4)

<h3>What is the coordinate of the point which divides a line segment in a specified ratio?</h3>

Suppose that there is a line segment \overline{AB}such that a point P(x,y) lying on that line segment \overline{AB} divides the line segment  \overline{AB} in m:n, then, the coordinates of the point P is given by:

(x,y) = \left( \dfrac{mx_2 + nx_1}{m+n} , \dfrac{my_2 + ny_1}{m+n} \right)

where we have:

  • the coordinate of A is (x_1, y_1)
  • and the coordinate of B is (x_2, y_2)

We're given that:

  • Coordinate of A is (x_1, y_1) = (-7,2)
  • Coordinate of B is (x_2, y_2) = (9.-6)
  • The point P lies on AB such that AP:BP=3:1 (so m = 3, and n = 1)

Let the coordinate of P be (x,y), then we get the values of x and y as:

(x,y) = \left( \dfrac{mx_2 + nx_1}{m+n} , \dfrac{my_2 + ny_1}{m+n} \right)\\\\(x,y) = \left( \dfrac{3(9) + 1(-7)}{3+1} , \dfrac{3(-6) + 1(2)}{3+1} \right)\\\\(x,y) = \left( \dfrac{20}{4} , \dfrac{-16}{4} \right) = (5,-4)

Thus, the coordinates of the point P which divides the line segment AB made by the points A(-7,2) and B(9,-6) is  (x,y) = (5,-4)

Learn more about a point dividing a line segment in a ratio here:

brainly.com/question/14186383

#SPJ1

4 0
2 years ago
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