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2 years ago

HELP ME PLS!!!!!!!!!!!!

Mathematics

1 answer:

melisa1 [442]2 years ago

6 0

Answer:

Slope of Line 1 = 4/3

Slope of Line 2 = 1/2

Slope of Line 3 = 4/3

For each pairs of lines, determine whether they're parallel, perpendicular or either.

Line 1 and Line 2: neither

Line 1 and Line 3: parallel

Line 2 and Line 3: neither

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You have a jar with 91 raisins. How many are left after you have eaten some?

Lemur [1.5K]

Answer: you choke and die by the time you hit 41 left :)

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3 years ago

The distance from House B to House D is 50 feet. The distance from House A to House C is 40 feet. What is the area of the

Naya [18.7K]

Answer:

200

Step-by-step explanation:

40*50=200

7 0

3 years ago

Someone please help

AleksandrR [38]

Replace y with 31:

31 = 7x -4

Add 4 to both sides:

35 = 7x

Divide both sides by 7:

x = 5

Input x = 5

6 0

2 years ago

Evaluate:<br> 12.16 x .13 =

nordsb [41]

Answer:

1.5808

Step-by-step explanation:

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3 years ago

A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.

pav-90 [236]

Answer:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.25$ represent the population standard deviation

n represent the sample size

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

3 0

2 years ago