43.8 = 100%
43.8/100 = 0.438 = 1%
0.438 x 45 = 19.71 = 45%
19.71 inches of rain falls in November.
600(1+0.08/5)^5=649560.3
The valur of Rs 600will decline to 649560.3in 5 years interest is 8%
First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
Answer:
B.20
hope it's helpful ❤❤❤❤❤❤❤❤❤❤
THANK YOU.
The temperature changed a total of 14° over the course of 7 hours with an average change of 2° per hour drop.
