Answer:

Step-by-step explanation:
The slope-intercept form of an equation of a line:

m - slope
b - y-intercept
We have the slope m = -1/5. Substitute:

Put the coordinates of the given point (-3, 7) to the equation:

<em>subtract 3/5 from both sides</em>

Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC=
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
there is no graph here to answer this
Third choice is correct hope I helped:3
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