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enot [183]
2 years ago
9

3. In what bases would 4025 be a legitimate numeral?

Mathematics
1 answer:
xxMikexx [17]2 years ago
4 0

Base six and greater would make 4025 a legitimate numeral.

Legitimate number in which bases a number is legitimate by comparing the largest digit with the base number. If the largest digit is less than the base number, it is a legitimate number.

We have number 4025 .So, here largest digit is 5.

As 4025 to be the Legitimate numeral ,the base number should be greater than the largest digit of the numeral. So the base number should be greater than 5 .

Therefore, any base of 6 or higher would make 4025 a legitimate numeral.

Learn more:brainly.com/question/10868065

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According to scientific research, the probability that a person between the ages of 20 and 25 having high blood pressure, is onl
boyakko [2]

Answer:

<h2>The probability is {\frac{83}{100} }^9 \times \frac{17}{100} + {\frac{83}{100} }^8 \times {\frac{17}{100} }^2 + {\frac{83}{100} }^{10}.</h2>

Step-by-step explanation:

The probability of having high blood pressure is 17%.

We need to find the probability of 2 or fewer have high blood pressure.

Possibility 1: No one have high blood pressure.

The probability is {\frac{100 -17}{100} }^{10} = {\frac{83}{100} }^{10}.

Possibility 2: Only one have high blood pressure.

The probability is {\frac{83}{100} }^9 \times \frac{17}{100}.

Possibility 3: 2 among the 10 have the high blood pressure.

{\frac{83}{100} }^8 \times {\frac{17}{100} }^2.

Any of the possibilities can happen.

Hence, the required probability is {\frac{83}{100} }^9 \times \frac{17}{100} + {\frac{83}{100} }^8 \times {\frac{17}{100} }^2 + {\frac{83}{100} }^{10}.

4 0
3 years ago
Please help!!!! 30 pts
Sedbober [7]

We are given equation:

5/6 x -2 = -2/3 x +1.

Note: when we have fracions in an equation, we always try to get rid fractions by removing denominator parts.

In the given equation we have 6 and 3 in denominator. So, we need to find the common denominator (lowest common denomiantor) of 6 and 3.

The lowest common denomiantor of 6 and 3 is 6.

So, equation is being multiplied by 6 on both sides.

Therefore,

Step 1) Multiply each side by LCD of fractions.

6 ( 5/6 x -2 ) = 6 (-2/3 x +1)

Step 2) Use distributive property to simplify above step, we get

6* 5/6 x = 5x

6 * -2 = -12

6 * -2/3 x = -4x and

6 * 1 = 6.

Therefore, we get

5x - 12 = -4x + 6 on simplifying second step.

Step 3) We use Addition property of Equality in third step.

Because we have -4x on right side, and the reverse operation of subtraction is addition.

5x - 12 = -4x + 6

+4x        +4x    Step 4) Here we just did simplification of above step.

____________________

9x -12  = 6

  +12   +12     Step 5) Again applied Addition property of Equality to get rid -12 from left side.  

_______________

9x  = 18         Step 6) Here we just did simplification of above step.

Step 7) Because 9 is being multiplied with x on left side. To get rid 9 from left side we need to apply reverse operation of multiplication.

Therefore, Division property of equality is used there by dividing 9 on both sides.

9x/9 = 18/9  

Step 8) Again did simplification of above step.

x=2 Final answer.

3 0
3 years ago
Read 2 more answers
What divides a two dimensional shape into two congruent shapes​
zaharov [31]

Answer:

Rectangle is a 2dimensional shape so, let me explain using it

The diagonal of a rectangle divides the rectangle into two triangles that are congruent and they are the same size and shape.

Another example is parallelogram

The diagonal of a parallelogram also divides the figure into two triangles that are congruent.

Step-by-step explanation:

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EXPAND:
Sladkaya [172]

Answer:

\displaystyle  A) 5\log( {x}^{}   )  +   2 \log( {y}^{} )

Step-by-step explanation:

we would like to expand the following logarithmic expression:

\displaystyle   \log( {x}^{5}  {y}^{2} )

remember the multiplication logarithmic indentity given by:

\displaystyle \rm  \log( \alpha  \times  \beta ) \iff  \log( \alpha ) +  \log( \beta )

so our given expression should be

\displaystyle   \log( {x}^{5}   )  +    \log( {y}^{2} )

by exponent logarithmic property we acquire:

\displaystyle   5\log( {x}^{}   )  +   2 \log( {y}^{} )

hence, our answer is A

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mylen [45]

Step-by-step explanation:

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