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Viktor [21]
2 years ago
10

Which statement is the best example of pseudoscience?

Physics
1 answer:
Nady [450]2 years ago
5 0
<span>pseudoscience includes beliefs theories, or practices that have been or are considered scientific, but have no basis in scientific fact.
This could mean the were disproved scientifically, can't be tested or lack evidence to support them.
Examples:Channeling- involves communicating with a spirit through a person

 Astrology- beliefs that humans are affected by the position of celestial bodies
</span>
You might be interested in
A cord of mass 0.65 kg is stretched between two supports 28 m apart. if the tension in the cord is 150 n, 2 how long will it tak
MaRussiya [10]
Ans: Time <span>taken by a pulse to travel from one support to the other = 0.348s
</span>
Explanation:
First you need to find out the speed of the wave.

Since
Speed = v = \sqrt{ \frac{T}{\mu} }

Where
T = Tension in the cord = 150N
μ = Mass per unit length = mass/Length = 0.65/28 = 0.0232 kg/m

So
v = \sqrt{ \frac{150}{0.0232} } = 80.41 m/s

Now the time-taken by the wave = t = Length/speed = 28/80.41=0.348s
5 0
2 years ago
Balance the following equations: CUCO3+H2SO4- CUSO4+H2O+CO2​
Setler79 [48]

Answer:

It is already balanced

Explanation:

It is already balanced

6 0
3 years ago
How could I tell if an egg is hard boiled or raw explain using Newton's law of motion
Thepotemich [5.8K]

Answer:

Explanation:

Newton's 2 nd law of motion tells that when equal torque is applied on object having higher moment of inertia , it will rotate slower .

Moment of inertia of boiled egg is higher because the whole egg rotates as s solid unit . Hence it will rotate slower or it rolls slower on an inclined surface .

In this way by applying Newton's law , we can identify raw or boiled egg .

6 0
2 years ago
In grinding a steel knife blade (specific heat = 0.11 cal/g-c),the metal can get as hot as 400C. If the blade has a mass of 80g,
babymother [125]

Answer:

33 g.

Explanation:

Assuming no heat transfer can be possible except for heat exchange between water and steel, we can say that the heat lost by the knife, must be equal to the heat gained by the water.

As we have a limit for the maximum temperature of both elements (once reached a final thermal equilibrium), of 100ºC, which means that the maximum allowable change in temperature will be of 300º C for the knife, and of 80º C for the water.

Empirically , it has been showed that for a heat exchange process using only conduction, the heat needed to raise the temperature of a body, is proportional to the mass, being the proportionality constant a factor that depends on the material, called specific heat.

So, we can write the following equation:

cs*mk*Δtk = cw*mw*Δtw

Replacing by the givens of the question, we have:

0.11 cal/gºC * 80 g * 300ºC = 1 cal/gºC*mw*80ºC

Solving for mw = 2,640 cal / 80 cal/g =33 g.

5 0
3 years ago
Suppose you take a 50gram ice cube from the freezer at an initial temperature of -20°C. How much energy would it take to complet
notsponge [240]

Answer:

The amount of energy required is 152.68\times 10^{3}Joules

Explanation:

The energy required to convert the ice to steam is the sum of:

1) Energy required to raise the temperature of the ice from -20 to 0 degree Celsius.

2) Latent heat required to convert the ice into water.

3) Energy required to raise the temperature of water from 0 degrees to 100 degrees

4) Latent heat required to convert the water at 100 degrees to steam.

The amount of energy required in each process is as under

1) Q_1=mass\times S.heat_{ice}\times \Delta T\\\\Q_1=50\times 2.05\times 20=2050Joules

where

'S.heat_{ice}' is specific heat of ice =2.05J/^{o}C\cdot gm

2) Amount of heat required in phase 2 equals

Q_2=L.heat\times mass\\\\\therefore Q_{2}=334\times 50=16700Joules

3) The amount of heat required to raise the temperature of water from 0 to 100 degrees centigrade equals

Q_3=mass\times S.heat\times \Delta T\\\\Q_1=50\times 4.186\times 100=20930Joules

where

'S.heat_{water}' is specific heat of water=4.186J/^{o}C\cdot gm

4) Amount of heat required in phase 4 equals

Q_4=L.heat\times mass\\\\\therefore Q_{4}=2260\times 50=113000Joules\\\\\\\\\\\\Thus the total heat required equals Q=Q_{1}+Q_{2}+Q_{3}+Q_{4}\\\\Q=152.68\times 10^{3}Joules

5 0
3 years ago
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