Answer:
The amount of baking powder for each batch
Explanation:
When doing an experiment, we have at least 2 variables involved:
- The independent variable, which is the variable whose value is changed by the operator, to test how the dependent variable will change
- The dependent variable, which is the variable whose value changes depending on the changing in the independent variable, and it is not directly controlled by the operator
For this experiment, we have:
- The amount of baking powder for each batch is the independent variable, since it is changed by Marcie
- The size of the cookies is the dependent variable, since Marcie wants to see how this quantity changes when the independent variable (the amount of baking powder) is changed
Answer:
Hope you understand this ans
Answer:
Distancia = 17,5 kilómetros.
Explanation:
Dados los siguientes datos;
Velocidad = 36 km/h
Tiempo = 0.5 horas
Para encontrar la distancia recorrida;
Distancia = velocidad * tiempo
Distancia = 35 * 0.5
Distancia = 17,5 kilómetros.
Por tanto, la distancia recorrida por el automóvil es de 17,5 kilómetros.
Answer:
+Q
Explanation:
As no electric field can exist (in electrostatic condition) inside a conductor, if we apply Gauss 'Law to a spherical gaussian surface with a radius just a bit larger than the distance of the inner surface to the center (but less tah the distance of the outer surface), the net flux through this surface must be zero, due to E=0 at any point of the gaussian surface.
Therefore, as the net flux must be proportional to the charge enclosed by the surface, it follows that Qenc = 0.
⇒ Qenc = Qc + Qin = -2Q + Qin = 0 ⇒ Qin = +2Q
So, if the net charge of the conductor is + 3Q (which must remain the same due to the conservation of charge principle) and no charge can exist within the conductor (in electrostatic conditions), we have the following equation:
Qnet = Qin + Qou = +3Q ⇒ +2Q + Qou = +3Q
⇒ Qou = +Q
Answer:![510. 12 cm^3](https://tex.z-dn.net/?f=510.%2012%20cm%5E3)
The volume of a cylindrical conduit,
where
is the inner radius,
is the outer radius, h is the length.
First of all, we would covert each parameter into centimeters.
length of the conduit, ![h=4 ft=4\times 30.48 cm=121.92 cm](https://tex.z-dn.net/?f=%20h%3D4%20ft%3D4%5Ctimes%2030.48%20cm%3D121.92%20cm)
outer radius, ![r_1=2.2/2 in =1.1 in= 1.1\times 2.54 cm=2.79 cm](https://tex.z-dn.net/?f=r_1%3D2.2%2F2%20in%20%3D1.1%20in%3D%201.1%5Ctimes%202.54%20cm%3D2.79%20cm)
inner radius, ![r_1=2/2 in =1 in= 2.54 cm](https://tex.z-dn.net/?f=r_1%3D2%2F2%20in%20%3D1%20in%3D%202.54%20cm)
Insert the values in the volume formula,
![V=3.14 \times (2.79^2-2.54^2) \times 121.92 cm^3=510. 12 cm^3](https://tex.z-dn.net/?f=V%3D3.14%20%5Ctimes%20%282.79%5E2-2.54%5E2%29%20%5Ctimes%20121.92%20cm%5E3%3D510.%2012%20cm%5E3)
Hence, the volume of metal in the conduit is 510. 12 cubic centimeters.