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Maru [420]
3 years ago
5

On which planet would your weight be the most and the least?

Physics
1 answer:
hoa [83]3 years ago
6 0

Answer:

Jupiter and neptune

Explanation:

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A skier stands at the top of a 50 meter slope. He then skis down the slope. What is his approximate speed at the bottom of the s
dedylja [7]

Answer:

31 m/s

Explanation:

7 0
2 years ago
Amy has a mass of 30 kg, and she is riding a skateboard traveling 5 m/s. What is her momentum
soldi70 [24.7K]
We Know, P = m*v
Here, m = 30 Kg
v = 5 m/s

Substitute it into the expression, 
P = 30*5 Kgm/s
P = 150 Kgm/s

So, your final answer is 150 Kg.m/s

Hope this helps!
3 0
3 years ago
Read 2 more answers
A crane lifts a 400 N crate full of baked beans 15 m. How much work was done by the crane?
damaskus [11]

Answer:

6000 J

Explanation:

work = F x S

work = 400 x 15

work = 6000 J

3 0
3 years ago
An X-Ray tube is an evacuated glass tube, where the electrons are produced at one end and accelerated by a strong electric field
lawyer [7]

Answer:

a) ΔV = 25.59 V, b)  ΔV = 25.59 V,  c)  v = 7 10⁴ m / s,  v/c= 2.33 10⁻⁴ ,

v/c% = 2.33 10⁻²

Explanation:

a) The speed they ask for electrons is much lower than the speed of light, so we don't need relativistic corrections, let's use the concepts of energy

starting point. Where the electrons come out

          Em₀ = U = e DV

final point. Where they hit the target

          Em_f = K = ½ m v2

energy is conserved

          Em₀ = Em_f

         e ΔV = ½ m v²

         ΔV = \frac{1}{2} mv²/e     (1)

If the speed of light is c and this is 100% then 1% is

         v = 1% c = c / 100

         v = 3 10⁸/100 = 3 10⁶6 m/ s

let's calculate

         ΔV = \frac{1}{2}  \frac{9.1 \ 10^{-31} (3 10^6 )^2 }{ 1.6 10^{-19} }

         ΔV = 25.59 V

b) Ask for the potential difference for protons with the same kinetic energy as electrons

             K_e = K_p

              K_p = ½ m v_e²

              K_p = \frac{1}{2}  9.1 10⁻³¹ (3 10⁶)²

              K_p = 40.95 10⁻¹⁹ J

we substitute in equation 1

              ΔV = Kp / M

              ΔV = 40.95 10⁻¹⁹ / 1.6 10⁻¹⁹

              ΔV = 25.59 V

notice that these protons go much slower than electrons because their mass is greater

c) The speed of the protons is

             e ΔV = ½ M v²

             v² = 2 e ΔV / M

             v² = \frac{2 \ 1.6 \ 10^{-19} \ 25.59 }{1.67 \ 10^{-27} }

              v² = 49,035 10⁸

               v = 7 10⁴ m / s

Relation

        v/c = \frac{7 \ 10^4 }{ 3 \ 10^8}

        v/c= 2.33 10⁻⁴

8 0
3 years ago
PHYSICAL SCIENCE HELP PLEASE !!!!! Picture below is for question 4
Eva8 [605]

Question 1) excited and moving around a lot.

Question 2) heat

Question 3) specific heat

Question 4) As temperature increases, energy transferred increases.

Hope these answers help!

3 0
4 years ago
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