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2 years ago

Study the image of the moving car.

Physics

2 answers:

Levart [38]2 years ago

8 0

While traveling downhill, the car’s potential is increasing and kinetic energy is decreasing

gayaneshka [121]2 years ago

6 0

Answer:

While traveling downhill, the car’s potential is increasing and kinetic energy is decreasing

Explanation:

hope this helps!

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When a red giant completes helium fusion and collapses, it becomes a ______.

Firdavs [7]

When a red giang complete helium fusion and collapses, it becomes a white dwarf. The correct option is C. White dwarf are very dense stars that are usually the size of a planet. It is a stellar core reminant which mainly made up of electron degenerated matters; its mass is comparable to that of the sun while its volume is comparable to that of the earth.

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3 years ago

Read 2 more answers

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alexandr1967 [171]

Answer:

1 is B 2 is D 3 is C

Explanation:

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3 years ago

Question in pic.. thanks!

11Alexandr11 [23.1K]

That's false. Displacement would be (r2 - r1) .

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3 years ago

Part complete Sound with frequency 1240 Hz leaves a room through a doorway with a width of 1.11 m . At what minimum angle relati

Sedbober [7]

Answer:

14.43° or 0.25184 rad

Explanation:

v = Speed of sound in air = 343 m/s

f = Frequency = 1240 Hz

d = Width in doorway = 1.11 m

Wavelength is given by

$\lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{343}{1240}\\\Rightarrow \lambda=0.2766\ m$

In the case of Fraunhofer diffraction we have the relation

$dsin\theta=\lambda\\\Rightarrow \theta=sin^{-1}\frac{\lambda}{d}\\\Rightarrow \theta=sin^{-1}\frac{0.2766}{1.11}\\\Rightarrow \theta=14.43^{\circ}\ or\ 0.25184\ rad$

The minimum angle relative to the center line perpendicular to the doorway will someone outside the room hear no sound is 14.43° or 0.25184 rad

6 0

3 years ago

A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an accelerat

Gekata [30.6K]

Answer:

The force required to move the quarterback with linebacker is 1215 N

Explanation:

$\text { Mass of linebacker } \mathrm{m}_{2}=150 \mathrm{kg}$

$\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}$

$\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}$

Using Newton's second law, it is established that F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object $\left(m_{1}+m_{2}\right)$

Now consider both $\mathrm{m}_{1} \text { and } \mathrm{m}_{2}$ as a system, so net force acting on the system is $\text { Force }=\left(m_{1}+m_{2}\right) a$

Substitute the given values in the above formula,

$\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}$

$\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}$

Force = 1215 N

1215 N is the force required to move the quarterback with linebacker.

5 0

3 years ago