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2 years ago

Study the image of the moving car.

Physics

2 answers:

Levart [38]2 years ago

8 0

While traveling downhill, the car’s potential is increasing and kinetic energy is decreasing

gayaneshka [121]2 years ago

6 0

Answer:

While traveling downhill, the car’s potential is increasing and kinetic energy is decreasing

Explanation:

hope this helps!

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What happens to the kinetic energy of a body when: a) the mass of the body is doubled at constant velocity? b) the velocity of t

blagie [28]

Using the formula KE=1/2mv^2

a: The kinetic energy doubles.
b: The kinetic energy quadruples.
c: The kinetic energy is cut in half.
Hopefully it’s clear how the formula can show you this.

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3 years ago

A forklift raises a 1,020 N crate 3.50 m up to a shelf. How much work is done by the forklift on the crate?

Anarel [89]

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3 years ago

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you're reading from the journal of a European explorer from the early 1600s. In one passage, the explorer describes itting on th

Zepler [3.9K]

Answer: horse latitudes

Explanation:

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3 years ago

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What is the current when the resistance is 5 ohms and the voltage is 10 volts?

Travka [436]

Ohm's Law states V = IR
So,
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2 years ago

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A bowling ball with a momentum of 18kg-m/s strikes a stationary bowling pin. After the collision, the ball has a momentum of 13k

Veronika [31]

Answer:

$14.98\ \text{kg m/s}$

$45.26^{\circ}$

Explanation:

$P_1$ = Initial momentum of the pin = 13 kg m/s

$P_i$ = Initial momentum of the ball = 18 kg m/s

$P_2$ = Momentum of the ball after hit

$55^{\circ}$ = Angle ball makes with the horizontal after hitting the pin

$\theta$ = Angle the pin makes with the horizotal after getting hit by the ball

Momentum in the x direction

$P_i=P_1\cos55^{\circ}+P_2\cos\theta\\\Rightarrow P_2\cos\theta=P_i-P_1\cos55^{\circ}\\\Rightarrow P_2\cos\theta=18-13\cos55^{\circ}\\\Rightarrow P_2\cos\theta=10.54\ \text{kg m/s}$

Momentum in the y direction

$P_1\sin55=P_2\sin\theta\\\Rightarrow P_2\sin\theta=13\sin55^{\circ}\\\Rightarrow P_2\sin\theta=10.64\ \text{kg m/s}$

$(P_2\cos\theta)^2+(P_2\sin\theta)^2=P_2^2\\\Rightarrow P_2=\sqrt{10.54^2+10.64^2}\\\Rightarrow P_2=14.98\ \text{kg m/s}$

The pin's resultant velocity is $14.98\ \text{kg m/s}$

$P_2\sin\theta=10.64\\\Rightarrow \theta=sin^{-1}\dfrac{10.64}{14.98}\\\Rightarrow \theta=45.26^{\circ}$

The pin's resultant direction is $45.26^{\circ}$ below the horizontal or to the right.

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2 years ago