Question

On level ground a shell is fired with an initial velocity of 49.0 m/s at 70.0 โ above the horizontal and feels no appreciable air resistance. Find the horizontal and vertical components of the shell's initial velocity.

Answer 1

Answer:

Horizontal component = 16.8 m/s

Vertical component = 46.0 m/s

Explanation:

If we denote the initial velocity by v and the angle above the horizontal by θ,

the horizontal component of this initial velocity is given by

$v_x = v\cos \theta$

$v_x = (49.0\text{ m/s})\cos\,(70.0^\circ) = 16.8\text{ m/s}$

The vertical component is given by

$v_y = v\sin\theta$

$v_x = (49.0\text{ m/s})\sin\,(70.0^\circ) = 46.0\text{ m/s}$