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Alex Ar [27]
2 years ago
10

On level ground a shell is fired with an initial velocity of 49.0 m/s at 70.0 โ above the horizontal and feels no appreciable ai

r resistance. Find the horizontal and vertical components of the shell's initial velocity.
Physics
1 answer:
xenn [34]2 years ago
3 0

Answer:

Horizontal component = 16.8 m/s

Vertical component = 46.0 m/s

Explanation:

If we denote the initial velocity by <em>v</em> and the angle above the horizontal by <em>θ</em>,

the horizontal component of this initial velocity is given by

v_x = v\cos \theta

v_x = (49.0\text{ m/s})\cos\,(70.0^\circ) = 16.8\text{ m/s}

The vertical component is given by

v_y = v\sin\theta

v_x = (49.0\text{ m/s})\sin\,(70.0^\circ) = 46.0\text{ m/s}

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Explanation:

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(D). We need to calculate the V_{R} when f = 2f_{c}

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V_{R}=4.561\ Volt

Hence, This is the required solution.

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