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Studentka2010 [4]
2 years ago
13

What determines who is the most important person

Physics
1 answer:
qwelly [4]2 years ago
5 0

Answer:

Putting your partner first means his or her needs, feelings, and wellbeing take priority over other people or things. A “sense of we” forms as you maintain this priority on purpose each day. You protect your relationship from being destroyed or damaged. You tend to your connection so it feels good to you b

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What is the weight of a 48kg rock?
IrinaK [193]

Answer:

48kg

Explanation:

4 0
2 years ago
Remember KE=M*V2/2…
 A model airplane moves twice as fast as another identical model airplane. Compared with the kinetic energy
pishuonlain [190]

Answer: 4 times as much

Explanation:

4 0
2 years ago
The maximum number of orbits in an atom is _____
svp [43]

Correct answer is:

<h2>The maximum number of orbits in an atom is <u>Seven.</u></h2><h3>Explanation:</h3>

Every energy level has a limited one orbital including two electrons. The orbits are settled in the sub-levels and there can be further than 1 sub-level as the number of energy levels rises. On energy level 1, there is 1 sub-level and 1 orbital. Energy level 2 can possess 2 sub-levels and 2 orbitals. These remain to develop as you progress from the nucleus of the atom, closing up with an infinite potential number of levels and orbits.

8 0
2 years ago
Convert the arc length of 3.05 degrees into meters.
statuscvo [17]

That depends on the circle's radius, which you neglected to mention.

If the radius is 1 meter, then an arc of 3.05 degrees is 5.32 centimeters long.

If the radius is 1 kilometer, then an arc of 3.05 degrees is 53.2 meters long.

7 0
3 years ago
If a spring is stretched 4m from its starting length when 20n of force is applied, then how much work (in joules) is done by the
lys-0071 [83]

ANSWER:

250 J

STEP-BY-STEP EXPLANATION:

F = 20N is required to stretch the spring by 4 meters

We know that the force is equal to:

F=k\cdot x

We solve for k (spring constant):

k=\frac{F}{x}=\frac{20}{4}=5\text{ N/m}

The work done in stretching the spring is given by the following equation (in this case the stretch is 10 meters:

\begin{gathered} W=\frac{1}{2}k\cdot x^2 \\ \text{ Replacing} \\ W=\frac{1}{2}\cdot5\cdot10^2 \\ W=250\text{ J} \end{gathered}

The work required is 250 joules.

5 0
1 year ago
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