Answer:
The coefficient of friction is 0.56
Explanation:
It is given that,
Mass of the automobile, m = 1400 kg
Speed of the automobile, v = 23 m/s
Radius of the track, r = 95 m
The automobile is moving in a circular track. The centripetal force is given by :
............(1)
Frictional force is given by :
...................(2)
= coefficient of friction
g = acceleration due to gravity
From equation (1) and (2), we get :
So, the coefficient of friction is 0.56. Hence, this is the required solution.
Answer:
0.859375c
31.03 seconds
Explanation:
v' = Velocity of my ship = 0.4 c
u = Velocity of rocket = 0.7 c
c = Speed of light =
s = Distance between my ship and enemy ship =
Relativistic addition of speed is given by
The speed of the missile is 0.859375c
Time is given by
It will take 31.03 seconds to reach me.
Answer:
13333.33 rev/min²
Explanation:
Given:
Initial angular speed of the automobile (ω₁) = 1260 rev/min
Final angular speed of the automobile (ω₂) = 3460 rev/min
Time interval for the change in speed (t) = 9.90 s
Angular acceleration of the automobile (α) = ?
Consider the sense of rotation to be positive. So, making use of the equation of motion of rotation, we have:
Rewriting in terms of 'α', we get:
Converting time 't' from seconds to minutes using conversion factor.
1 sec =
So, 9.90 s =
Plug in all the given values and solve for 'α'. This gives,
Therefore, the angular acceleration in revolutions per minute squared is 13333.33 rev/min².
That's the average <em>acceleration</em> during that interval time.