Question

A stone is thrown with an initial speed of 12 m/s at an angle of 30o above the horizontal from the top edge of a cliff. If it takes the stone 5.6 s to reach the bottom, how far does the stone travel horizontally

Answer 1

Answer:

$d=58m$

Explanation:

From the question we are told that:

Initial Speed $U=12m/s$

Time $T=5.6s$

Angle $\theta=30$

Generally the  Newton's equation for motion is mathematically given by

$d=d'+ut+\frac{at^2}{2}$

$d=12cos30*5.6$

$d=58m$