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poizon [28]
3 years ago
5

Jude has a mutation in the gene that codes for a certain digestive enzyme. However, these enzymes function normally.

Chemistry
1 answer:
Molodets [167]3 years ago
6 0

Answer:

b

Explanation:

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Methane (CH4), ammonia (NH3), and oxygen can react to form hydrogen cyanide (HCN) and water according to this equation:
disa [49]
Assuming the molar mass of oxygen is 18.01, you only need 16 grams (B) of oxygen because the molar mass of hydrogen is about 1 gram.
16+1+1=18
7 0
3 years ago
How do hydrogen fuel cells work​
Maksim231197 [3]
Fuel cells work by passing hydrogen through the anode of a fuel cell and oxygen through the cathode. On the anode site, hydrogen molecules are split into electrons and protons. They have a high efficiency therefore these fuel cells are also considered to be very clean plus a fuel cells only by-products are electricity, excess heat, and water.
4 0
4 years ago
CH4 with pressure 1 atm and volume 10 liter at 27°C is passed into a reactor with 20% excess oxygen, how many moles of oxygen is
BaLLatris [955]

Answer : The moles of O_2 left in the products are 0.16 moles.

Explanation :

First we have to calculate the moles of CH_4.

Using ideal gas equation:

PV=nRT

where,

P = pressure of gas = 1 atm

V = volume of gas = 10 L

T = temperature of gas = 27^oC=273+27=300K

n = number of moles of gas = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

(1atm)\times (10L)=n\times (0.0821L.atm/mol.K)\times (300K)

n=0.406mole

Now we have to calculate the moles of O_2.

The balanced chemical reaction will be:

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that,

As, 1 mole of CH_4 react with 2 moles of O_2

So, 0.406 mole of CH_4 react with 2\times 0.406=0.812 moles of O_2

Now we have to calculate the excess moles of O_2.

O_2 is 20 % excess. That means,

Excess moles of O_2 = \frac{(100 + 20)}{100} × Required moles of O_2

Excess moles of O_2 = 1.2 × Required moles of O_2

Excess moles of O_2 = 1.2 × 0.812 = 0.97 mole

Now we have to calculate the moles of O_2 left in the products.

Moles of O_2 left in the products = Excess moles of O_2 - Required moles of O_2

Moles of O_2 left in the products = 0.97 - 0.812 = 0.16 mole

Therefore, the moles of O_2 left in the products are 0.16 moles.

7 0
3 years ago
How many hydrogen atoms are in the following molecule of ammonium sulfide? (NH4)2S
Lelechka [254]
The are eight hydrogen atoms in ammonium sulfide because there are 2 molecules of ammonium.
3 0
3 years ago
Read 2 more answers
If a solution has a perfect neutral pH, what is the concentration of hydrionium ions in the solution
Oksana_A [137]

Neutral pH means a pH of 7, yes? Recall that 'pH' means the POWER of Hydrogen. You should be familiar with the equation : pH = -log[H+].

In this case, 7 = log[H+].

Mathematically rearranged, this means that to find H+ concentration,

[H+] = 10 ^-pH.

In this case, [H+] = 10 ^-7.

I am assuming this is conducted at a standard 25 degrees. The auto-dissociation formula of water is this: Kw = [H3O+] x [OH-] at 25 degrees.

The concentration of Hydronium is the same as the concentration of hydrogen, 10 ^-7.  mol/L.

There's your answer!

7 0
4 years ago
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