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3 years ago

(a) Why is it important that scientists publish their theories?

1 answer:

3 0

It’s important because it provides so other scientists can repeat the experiment to prove if that theory is true or not.

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Which one of these is most likely to gain electrons and which one is most likely to lose electrons? (And please explain why)

Lelu [443]

Answer:

(I). The most likely to lose electron is Rubidium

(II). The most likely to lose electron is Bromine

Explanation:

Given that,

Radium, Indium, Phosphorus, Tellurium, Bromine and Rubidium

We know that,

Metal :

They atom which to lose electron these is called metal.

When the atom loses the electron then the positive charge come on the atom.

The most likely to lose electron is Rubidium

Non metal :

They atome which is gains electron. It is called non metal.

So, we can say that, the non metal gains electron.

When the atom gains the electron then the negative charge come on the atom.

The most likely to gain electron is Bromine

Hence, This is required answer.

8 0

4 years ago

A plant uses the energy from sunlight to create oxygen and glucose from carbon dioxide and water. Which statement is true about

Roman55 [17]

Answer:d

Explanation:so it can grow

7 0

3 years ago

How many moles is 24 grams of carbon?

Alex

N=24/12
n=2

where n= no. of moles

6 0

3 years ago

Read 2 more answers

The aromatic hydrocarbon cymene (C10H14) is found in nearly 100 spices and fragrances, including coriander, anise, and thyme. Th

andrezito [222]

Answer : The thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole

Explanation :

First we have to calculate the heat released by the combustion.

$q=c\times \Delta T$

where,

q = heat released = ?

$c$ = specific heat of calorimeter = $3.640kJ/^oC$

$\Delta T$ = change in temperature = $19.35^oC$

Now put all the given values in the above formula, we get:

$q=3.640kJ/^oC\times (19.35)^oC$

$q=70.43kJ$

Thus, the heat released by the combustion = 70.43 kJ

Now we have to calculate the molar enthalpy combustion.

$\Delta H=-\frac{q}{n}$

where,

$\Delta H$ = molar enthalpy combustion = ?

q = heat released = 70.43 kJ

n = number of moles cymene = $\frac{\text{Mass of cymene}}{\text{Molar mass of cymene}}=\frac{1.608g}{164.22g/mol}=0.009792mole$

$\Delta H=-\frac{70.43kJ}{0.009792mole}=-7193kJ/mole$

Therefore, the thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole

4 0

3 years ago

A sample in the lab is found to contain 0.450 g magnesium and 2.95 g bromine. what is the empirical formula of the sample?

Rasek [7]

We need to find the number of moles that each of the given substances. The molar mass of magnesium is 24.3 g/mol and Bromine has a molar mass of 79.90 g/mol. From the given mass of each species, the moles of Mg and Br are 0.018 and 0.369 respectively. There are 2 Br in one Mg. The sample is MgBr2.

3 0

4 years ago

Read 2 more answers