If you divide 2380 by 4, it will give you 10% of the whole:
1380/4=345
Then you can times 345 by 6 To find the 60%:
345*6=2070
PS Please check my calculations with a calculator as I worked these out in my head.
Answer: SHEEEESHOOOOOO yesssirrrr big brainnnnnnn :clap clap:
Answer:
The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median
6w-y=2z
6w=2z+y
w=(2z+y):6
w=(z:3)+(y:6)
