Question

A chemist has to prepare 250.0 mL of a 0.300 M Na2SO4(aq) solution. What mass, in grams, of sodium sulfate (formula mass 142.05 g/mol) would they use

Answer 1

The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g

How to determine the mole of sodium sulphate Na₂SO₄

• Volume = 250 mL = 250 / 1000 = 0.25 L
• Molarity = 0.3 M

• Mole of Na₂SO₄ =?

Mole = Molarity x Volume

Mole of Na₂SO₄ = 0.3 × 0.25

Mole of Na₂SO₄ = 0.075 mole

How to determine the mass of sodium sulphate Na₂SO₄

• Molar mass of Na₂SO₄ = 142.05 g/mol
• Mole of Na₂SO₄ = 0.075 mole

• Mass of Na₂SO₄ =?

Mass = mole × molar mass

Mass of Na₂SO₄ = 0.075 × 142.05

Mass of Na₂SO₄ = 10.65 g

Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.

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