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1 year ago

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A chemist has to prepare 250.0 mL of a 0.300 M Na2SO4(aq) solution. What mass, in grams, of sodium sulfate (formula mass 142.05

g/mol) would they use

1 answer:

Sedbober [7]1 year ago

6 0

The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g

<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>

Volume = 250 mL = 250 / 1000 = 0.25 L
Molarity = 0.3 M

Mole of Na₂SO₄ =?

Mole = Molarity x Volume

Mole of Na₂SO₄ = 0.3 × 0.25

Mole of Na₂SO₄ = 0.075 mole

<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>

Molar mass of Na₂SO₄ = 142.05 g/mol
Mole of Na₂SO₄ = 0.075 mole

Mass of Na₂SO₄ =?

Mass = mole × molar mass

Mass of Na₂SO₄ = 0.075 × 142.05

Mass of Na₂SO₄ = 10.65 g

Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.

Learn more about molarity:

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In this case, according to the given ionization of magnesium hydroxide, it is possible for us to set up the following reaction:

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