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Aliun [14]
2 years ago
10

04 Question (1 point)

Chemistry
1 answer:
VLD [36.1K]2 years ago
6 0
Ummmm what did you say???
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Seafood Watch has made several unsustainable fishing practices illegal. true or false
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Answer:

True

Explanation:

As per the standards of fishing outlined by Seafood watch, fishing related to endangered species , threatened species, over fished or depleted species has been restricted to allow these fishes to recover otherwise they may become extinct. Catching of mammals, sharks, finish, turtles, shellfish  etc. have been strictly restricted . Not only this several fishing practices have also been restricted such as sea floor netting , Night setting , Side setting, Line shooter and mainline  tension, bait caster, live  bait, thawing bait  etc.

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A community needs more electrical energy. The community is located in an
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Iron and aluminim are examples of _________. a. pure substances b. compounds
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Element X forms an oxide with chemical formula X20. Experimental tests show that X20 contains 25.8 % oxygen, and x contains 74.2
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2 years ago
"11. Barium nitrate reacts with aqueous sodium sulfate to produce solid barium sulfate and aqueous sodium nitrate. Abigail place
Amanda [17]

Answer:

44 mL of Na2SO4

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

Ba(NO3)2 (aq) + Na2SO4 (aq) —> BaSO4 (s) + 2NaNO3 (aq)

Step 2:

Determination of the number of mole of Ba(NO3)2 in 20.00 mL of 0.500 M barium nitrate (Ba(NO3)2). This is illustrated below:

Molarity of Ba(NO3)2 = 0.5 M

Volume of solution = 20 mL = 20/1000 = 0.02 L

Mole of solute (Ba(NO3)2) =?

Molarity = mole /Volume

0.5 = Mole of Ba(NO3)2 / 0.02

Cross multiply to express in linear form

Mole of Ba(NO3)2 = 0.5 x 0.02

Mole of Ba(NO3)2 = 0.01 mole

Step 3:

Determination of the number of mole of Na2SO4 that reacted.

Ba(NO3)2 (aq) + Na2SO4 (aq) —> BaSO4 (s) + 2NaNO3 (aq)

From the balanced equation above,

1 mole of Ba(NO3)2 reacted with 1 mole of Na2SO4.

Therefore, 0.01 mole of Ba(NO3)2 will also react with 0.01 mole of Na2SO4.

Step 4:

Determination of the volume of Na2SO4 needed for the reaction. This is illustrated below:

Mole of Na2SO4 = 0.01 mole

Molarity of Na2SO4 = 0.225M

Volume =?

Molarity = mole /Volume

0.225 = 0.01 / volume

Cross multiply to express in linear form

0.225 x Volume = 0.01

Divide both side by 0.225

Volume = 0.01/0.225

Volume of Na2SO4 = 0.044 L

Converting 0.044 L to mL, we have

Volume of Na2SO4 = 0.044 x 1000

Volume of Na2SO4 = 44 mL

Therefore, 44 mL of Na2SO4 is needed for the reaction

6 0
3 years ago
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