Point K is on line segment JL. Given KL = 6 and JK = 14, determine the length JL.

Lin runs 5 laps around a track in 6 minutes. How many minutes per lap is that? ___minutes How many laps per minute is that? ___

snow_lady [41]

Answer:

a. 1.2 minutes

b. 0.83 laps

c. 25.2 minutes

Step-by-step explanation:

Lin runs 5 laps around a track in 6 minutes.

a. How many minutes per lap is that?

5 laps = 6 minutes

1 laps = x minutes

Cross Multiply

x minute × 5 laps = 6 minutes × 1 laps

x minute = 6 minutes × 1 laps/5 laps

x laps = 1.2 minutes

Hence, it is 1.2 minutes per lap

b. How many laps per minute is that?

6 minutes = 5 laps

1 minute = x laps

Cross Multiply

6 minutes × x laps = 1 minute × 5 laps

x laps = 1 minute × 5 laps/6 minutes

x laps = 0.8333333333 laps

Hence, it is 0.83 laps per minute.

c. If Lin runs 21 laps at the same rate,

5 laps = 6 minutes

21 laps = x minutes

Cross Multiply

x minute × 5 laps = 6 minutes × 21 laps

x minute = 6 minutes × 21 laps/5 laps

x laps = 25.2 minutes

Hence, it takes her 25.2 minutes

3 0

3 years ago

Solve 6/25x = 9/10 ———

kompoz [17]

Answer:

x = 15/4

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How do I solve question 5?

Nezavi [6.7K]

A) x^2 + y^2 = 80
B) x * y = 12

What is x^2 -y^2?
B) x * y = 12
So y = 12 / x
A) x^2 + (12/x)^2 = 80
x^2 + (12/x)^2 = 80
x^2 + (144/x^2) = 80
Multiplying each side by x^2
x^4 + 144 = 80x^2
x^4 -80x^2 + 144 = 0
X = 1.355 (found by trial and error)
Y = 8.85608 (found by trial and error)

3 0

3 years ago

5+ 3x - 37 = 6x + 23 - 8x what is the value for x

iris [78.8K]

Answer:

The value of X is 11

X=11

Step-by-step explanation:

Isolate the variable by dividing each side by the factors that don't contain the cariable.

4 0

2 years ago

In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equa

arlik [135]

Answer:

Yes. At this significance level, there is evidence to support the claim that there is a difference in the ability of the brands to absorb water.

Step-by-step explanation:

The question is incomplete:

The significance level is 0.05.

The data is:

Brand X: 91, 100, 88, 89

Brand Y: 99, 96, 94, 99

Brand Z: 83, 88, 89, 76

We have to check if there is a significant difference between the absorbency rating of each brand.

Null hypothesis: all means are equal

$H_0:\mu_x=\mu_y=\mu_z$

Alternative hypothesis: the means are not equal

$H_a: \mu_x\neq\mu_y\neq\mu_z$

We have to apply a one-way ANOVA

We start by calculating the standard deviation for each brand:

$s_x^2=30,\,\,s_y^2=6,\,\,s_z^2=35.33$

Then, we calculate the mean standard error (MSE):

$MSE=(\sum s_i^2)/a=(30+6+35.33)/3=71.33/3=23.78$

Now, we calculate the mean square between (MSB), but we previously have to know the sample means and the mean of the sample means:

$M_x=92,\,\,M_y=97,\,\,M_z=84\\\\M=(92+97+84)/3=91$

The MSB is then:

$s^2=\dfrac{\sum(M_i-M)^2}{N-1}\\\\\\s^2=\dfrac{(92-91)^2+(97-91)^2+(84-91)^2}{3-1}\\\\\\s^2=\dfrac{1+36+49}{2}=\dfrac{86}{2}=43\\\\\\\\MSB=ns^2=4*43=172$