Point K is on line segment JL. Given KL = 6 and JK = 14, determine the length JL.

Solve for d. d^3 + 27 = 0 Write your answers in simplified, rationalized form.

tester [92]

Answer:

d=-3

Step-by-step explanation:

d3+27=0

Step 1: Subtract 27 from both sides.

d3+27−27=0−27

d3=−27

Step 2: Take cube root.

d=(−27)(

1

3

)

d=−3

7 0

3 years ago

Read 2 more answers

Tayâ€“Sachs Disease Tayâ€“Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carri

BARSIC [14]

Answer:

a) 0.0156 = 1.56% probability that all children will develop the disease.

b) 0.4219 = 42.19% probability that only one child will develop the disease.

c) 0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they carry the disease, or they do not. The probability of a children carrying the disease is independent of any other children, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that their offspring will develop the disease is approximately .25.

This means that $p = 0.25$

Three children:

This means that $n = 3$

Question a:

This is P(X = 3). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{3,3}.(0.25)^{3}.(0.75)^{0} = 0.0156$

0.0156 = 1.56% probability that all children will develop the disease.

Question b:

This is P(X = 1). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{3,1}.(0.25)^{1}.(0.75)^{2} = 0.4219$

0.4219 = 42.19% probability that only one child will develop the disease.

c. The third child will develop Tayâ€“Sachs disease, given that the first two did not.

Third independent of the first two, so just multiply the probabilities.

First two do not develop, each with 0.75 probability.

Third develops, which 0.25 probability. So

$p = 0.75*0.75*0.25 = 0.1406$

0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

6 0

3 years ago

Suzi tiene $20 dólares en una cuenta de ahorros. El tipo de intereses es del 10% anual. Cuanto ganara en un año

Damm [24]

Responder:

$ 22

Explicación paso a paso:

Monto principal = $ 20

Tasa de interés = 10% = 10/100 = 0.1

Tiempo = 1 año

Cantidad ganada después de 1 año:

Principal (1 + (tasa de interés * tiempo))

$ 20 (1 + (0,1 * 1))

$ 20 (1 + 0.1)

$ 20 (1,1)

$ 22

Ganará $ 22 después de un año.

6 0

3 years ago

A player chooses one of the numbers 1 through 4. After the choice has been made, two regular four-sided (tetrahedral) dice are r

d1i1m1o1n [39]

Answer: $=\frac{-1}{16}$

Step-by-step explanation:

given data:

number to be chosen from = 1,2,3,4.

Solution:

ways the number can show

$2*3*1=6$ ways for your number to appear once.

$1*1=1$ ways for your number to appear twice.

$3*3=9$ ways for your number not to appear at all

$= \frac{6(1) + 1(2) - 9(1)}{16}$

$= \frac{6+2-9}{16}$

$=\frac{-1}{16}$

expected return of the player is $=\frac{-1}{16}$

4 0

3 years ago

There are 154 players on 11 teams . How many players are on one team

jarptica [38.1K]

Answer:

there are 14 on a single team

Step-by-step explanation:

154÷11=14

Or you can do this

11 • 14

add 11 14 times you get 154

7 0

3 years ago