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3 years ago

What is the next letter a z b y c x d

2 answers:

6 0

The next logical letter would be w.
This pattern starts at the first letter, then the last letter, then the second letter, then the second to last, the third, third to last, and so on.

Liono4ka [1.6K]3 years ago

5 0

The next letter is w.

a, __, b, __, c, __ d, __
_, z , _, y , _, x ,_, W

get the picture?

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Find the area of the following rectangle,

lesya692 [45]

Answer:

55/72 feet squared

Step-by-step explanation:

The area of a rectangle is Length x Height, or Width x Height.

Here, we have a width of 5/6 feet and a height of 11/12 feet.

We multiple 5/6 and 11/12 to get 55/72 feet squared.

4 0

3 years ago

Can somebody help me with this question !

Pavlova-9 [17]

Answer:

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3 years ago

1. Write the equation of the line that is described. Give your answer in slope-intercept form.

kirill115 [55]

Answer:

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Step-by-step explanation:

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3 years ago

Need help ASAP (You dont have to show work, just answer it)

anyanavicka [17]

Answer:

$50.40 is the answer

Step-by-step explanation:

12% of 45 is 5.40 so if we add $5.40 and $45 we get $50.40

hope this helps ^-^ have a wonderful day

4 0

2 years ago

Read 2 more answers

Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2

34kurt

$\displaystyle\iint_Rye^x\,\mathrm dA=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=5}r^2\sin\theta e^{r\cos\theta}\,\mathrm dr\,\mathrm d\theta$

which follows from the usual change of coordinates via

$\begin{cases}\mathbf x(r,\theta)=r\cos\theta\\\mathbf y(r,\theta)=r\sin\theta\end{cases}$

and Jacobian determinant

$|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|$

Swap the order, so that the integral is

$\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr$

and now let $\sigma=r\cos\theta$ , so that $\mathrm d\sigma=-r\sin\theta$ . Now, you have

$\displaystyle\int_{r=0}^{r=5}\int_{\sigma=0}^{\sigma=r}re^\sigma\,\mathrm d\sigma\,\mathrm dr=\int_{r=0}^{r=5}r(e^r-1)\,\mathrm dr=4e^5-\dfrac{23}2$

7 0

3 years ago