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2 years ago

Please help asap tysm n ily <3

Mathematics

2 answers:

adoni [48]2 years ago

6 0

Answer: They left at 2:45 pm

Step-by-step explanation:

They started shopping at 11:45 am.

It took 1 hour to shop and 30 minutes to eat, again it took 1 hour 30 min to play games, if you add up, total 3 hours .

melamori03 [73]2 years ago

4 0

Hey there!

Started at 11:45 AM

To find the time when they left we add the total of time spent to 11:45

=> 3 hours+ 11:45

=> 2:45

Therefore, They left at 2:45 PM

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$\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}$

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$\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}$

2. a. The given ODE is separable as

$x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}$

Using the result of part (1), integrating both sides gives

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$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)$

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$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)$

$\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|$

$\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|$

$\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}$

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$y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}$

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