1) Factor out common terms in the first two terms, then in the last two terms
{x}^{3}(x+2)-2(x+2)
2) Factor out the common term x+2
(x+2)({x}^{3}-2)
Done!
Answer:
lol it so easy man 3(y+4) is the answer
2 apples in the partly filled tray, 11 tents are needed for all the children
Answer:
its 84 but tysm thats so sweet
Step-by-step explanation:
F(x)=2x^2-x-6
Factoring:
f(x)=2(2x^2-x-6)/2=(2^2x^2-2x-12)/2=[(2x)^2-(2x)-12]/2
f(x)=(2x-4)(2x+3)/2=(2x/2-4/2)(2x+3)→f(x)=(x-2)(2x+3)
g(x)=x^2-4
Factoring
g(x)=[sqrt(x^2)-sqrt(4)][sqrt(x^2)+sqrt(4)]
g(x)=(x-2)(x+2)
f(x)/g(x)=[(x-2)(2x+3)] / [(x-2)(x+2)
Simplifying:
f(x)/g(x)=(2x+3)/(x+2)
Answer: Third Option (2x+3)/(x+2)
