The answer is answer choice B,
B) {-2, -1, 0, 1}
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I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey
20%, there are 100 people so you base each person as a percentage.
Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
the first one is left and the second one is up
7 7/9 clergs.
wergs= w
nergs= n
clergs= c
3w= 4n, so 5w= 6 2/3n
Since 6n=7c, then 6 2/3n= 7 7/9n
Hope that answered your question!!