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vovangra [49]
3 years ago
14

A perfectly spherical orange is split into four equal sections. if the radius of the orange is 4 centimeters, what is the total

surface area of one slice? 16π cm2 32π cm2 24π cm2 64π cm2
Physics
2 answers:
Fantom [35]3 years ago
6 0

The total surface area of one slice will be 64 π cm².

<h3>What is the total surface area?</h3>

The total surface area includes the base as well as the curving component. It is the whole area covered by the object's surface.

The total area of a form with a curved surface and base is equal to the sum of the two areas.

The total surface area of the sphere will be;

\rm A=4 \pi r^2 \\\\ \rm A=4 \times \pi  (4)^2 \\\\ \rm A=64 \pi \  cm^2

Hence the total surface area of one slice will be 64 π cm².

To learn more about the total surface area refer to the link;

brainly.com/question/8419462

Morgarella [4.7K]3 years ago
5 0

Answer:

32

Explanation:

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g a small smetal sphere, carrying a net charge is held stationarry. what is the speed are 0.4 m apart
Veseljchak [2.6K]

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The speed of q₂ is 4\sqrt{10}\ m/s

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Distance = 0.4 m apart

Suppose, A small metal sphere, carrying a net charge q₁ = −2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q₂ = −8μC and mass 1.50g, is projected toward q₁. When the two spheres are 0.800m apart, q₂ is moving toward q₁ with speed 20m/s.

We need to calculate the speed of q₂

Using conservation of energy

E_{i}=E_{f}

\dfrac{1}{2}mv_{i}^2+\dfrac{kq_{1}q_{2}}{r_{i}}=\dfrac{kq_{1}q_{2}}{r_{f}}+\dfrac{1}{2}mv_{f}^2

\dfrac{1}{2}m(v_{i}^2-v_{f}^2)=kq_{1}q_{2}(\dfrac{1}{r_{f}}-\dfrac{1}{r_{i}})

Put the value into the formula

\dfrac{1}{2}\times1.5\times10^{-3}(20^2-v_{f}^2)=9\times10^{9}\times-2\times10^{-6}\times-8\times10^{-6}(\dfrac{1}{(0.4)}-\dfrac{1}{(0.8)})

0.00075(400-v_{f}^2)=0.18&#10;

400-v_{f}^2=\dfrac{0.18}{0.00075}

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v_{f}^2=160

v_{f}=4\sqrt{10}\ m/s

Hence, The speed of q₂ is 4\sqrt{10}\ m/s

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