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Svetradugi [14.3K]
3 years ago
9

A wheel rotates about a fixed axis with an initial angular velocity of 24 rad/s. During a 4 s interval the angular velocity decr

eases to 14 rad/s. Assume that the angular acceleration is constant during the 4 s interval. How many radians does the wheel turn through during the 4 s interval
Physics
1 answer:
netineya [11]3 years ago
7 0

Answer:

\theta=76\ rad

Explanation:

Hoven that,

Initial angular velocity of the wheel = 24 rad/s

Final angular velocity = 14 m/s

Time, t = 4 s

We need to find how many radians does the wheel turn through during the 4 s interval. Let the displacement is \theta. Using second equation of rotational kinematics to find it such that,

\theta=\omega_i t+\dfrac{1}{2}\alpha t^2

Where

\alpha is angular acceleration

\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{14-24}{4}\\\\\alpha =-2.5\ rad/s^2

So,

\theta=24\times 4+\dfrac{1}{2}\times (-2.5)\times 4^2\\\\\theta=76\ rad

So, it will turn 76 radian during the 4 s interval.

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A spacecraft is fueled using hydrazine (N2H4; molecular weight of 32 grams per mole [g/mol]) and carries 1640 kilograms [kg] of
Sauron [17]

Answer:

The value is t = 689.029 \  hours

Explanation:

From the question we are told that

The molar mass of hydrazine is Z =  32 g/mol = \frac{32}{1000} = 0.032 \  kg/mol

The initial temperature is T_i  =  -186 ^o F = (-186-32) *\frac{5}{9} +273.15 = 152\ K

The final temperature is T_f  =  78 ^o F = (78-32) *\frac{5}{9} +273.15 = 298.7 \ K

The specific heat capacity is c_h  =  0.099 [kJ/(mol K)] = 0.099 *10^3 J/(mol/K)

The power available is P = 300 \ W

The mass of the fuel is m =   1640 \  kg

Generally the number of moles of hydrazine present is

n  =  \frac{m}{Z}

=> n  =  \frac{1640}{= 0.032}

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Generally the quantity of heat energy needed is mathematically represented as

Q =  n * c_h * (T_f -T_i)

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=> Q =  7.441516913 * 10^{8} \  J

Generally the time taken is mathematically represented as

t =  \frac{Q}{P}

=> t =  \frac{7.441516913 * 10^{8} }{300}

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Here, F is the force exerted on an object under tensio, A is the area of the cross-section perpendicular to the applied force, \Delta L is the amount by which the length of the object changes and  L_0 is the original length of the object. In this case the force is the weight of the mass:

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