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2 years ago

Which best describes the way a sound wave is sent through the radio

Physics

2 answers:

wlad13 [49]2 years ago

6 0

Answer:

sound wave-electrical wave-radio wave

Zinaida [17]2 years ago

6 0

Answer:

Explanation:

on edg

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In 0.601 s, a 13.1-kg block is pulled through a distance of 4.19 m on a frictionless horizontal surface, starting from rest. The

Naya [18.7K]

Answer:

0.615 m

Explanation:

We need to determine the force on the spring first. By Newton's second law of motion, force is the product of the mass and acceleration. The mass is given.

The acceleration is determined using the equation of motion.

Given parameters:

Initial velocity, u = 0.00 m/s

Distance, s = 4.19 m

Time, t = 0.601 s

We use the equation

$s = ut+\frac{1}{2}at^2$

With u = 0.00 m/s,

$s = \frac{1}{2}at^2$

$a = \dfrac{2s}{t^2}$

$a = \dfrac{2\times4.19\text{ m}}{(0.601\text{ s})^2} = 23.2\text{ m/s}^2$

The force is

$F = (13.1\text{ kg})(23.2\text{ m/s}^2) = 303.92 \text{ N}$

From Hooke's law, the extension, e, of a string is given by

$e = \dfrac{F}{k}$

where k is the spring constant.

Hence,

$e = \dfrac{303.92\text{ N}}{494\text{ N/m}} = 0.615\text{ m}$

4 0

2 years ago

you serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has how much energy

Len [333]

Answer:

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

8 0

2 years ago

A textbook is dropped from a second floor window and falls to the ground. What happens to the acceleration as the book falls to

Sav [38]

Answer:

The correct option is;

The acceleration remains constant

Explanation:

The acceleration is due to the force of gravitational attraction between the text book and the Earth

According to Newton's law of gravitation, there is an attractive force between all objects given by the following relation;

F = G×M₁×m₂/r²

Where;

G, M₁, m₂, and r are constant such that we have;

G×M₁/r² = Constant = The acceleraton due to gravity, g

F = g×m₂

So the acceleration of the textbook as it is being attracted by the force of gravity towards the ground (Earth) is remains constant.

6 0

2 years ago

A child in a boat throws a 5.90-kg package out horizontally with a speed of 10.0 m/s. The mass of the child is 25.0 kg and the m

Troyanec [42]

-0.930 m/s is the velocity of the boat.

<h3>Given:</h3>

Mass of child and boat , $m_1$ = (25.0 + 38.4 )kg

= 63.4 kg

Mass of the package, $m_2$ = 5.90 kg

Velocity of package thrown from boat , $v_2$ = 10.0m/s

$v_1 =?$

Initial velocity v = 0 m/s

As the boat is at rest, $(m_1 + m_2) v=0$

According, to the law of conversation of momentum;

∴ Momentum before = Momentum after

$( m_1 + m_2 ) v = m_1v_1 + m_2v_2\\0 = m_1v_1 + m_2v_2\\0 = 63.4 v_1 + 5.90*10.0\\63.4 v_1 = - 5.9\\v_1 = - 0.930 m/s$

Negative direction shows the velocity in the direction opposite to the motion of the package.

Therefore, -0.930 m/s is the velocity of the boat.

Learn more about velocity here:

brainly.com/question/3953231

#SPJ1

5 0

1 year ago

A horizontal force pushes a 26 kg sled along a driveway for a distance of 36 m. If the coefficient of sliding friction is 0.2, w

SVETLANKA909090 [29]

Answer:1834.56 joules

Explanation:

Distance=36m

Coefficient of friction=0.2

Mass=26kg

Acceleration due to gravity=9.8m/s^2

Reaction=mass x acceleration due to gravity

Reaction=26 x 9.8

Reaction=254.8N

Coefficient of friction=frictional force ➗ reaction

0.2=frictional force ➗ 254.8

Frictional force=0.2 x 254.8

Frictional force=50.96N

work=friction force x distance

Work=50.96 x 36

Work=1834.56

Work=1834.56 joules

8 0

3 years ago