<h3><em>when gravity pulls a skydiver towards the Earth the reaction forces</em></h3>
- <em>A.</em><em> </em><em>the</em><em> weight of the skydiver </em>
<h2><em>hope</em><em> it</em><em> helps</em><em>!</em></h2>
Answer:
608.4m/s
Explanation:
We are given that
Mass of Sleigh,M=1200 kg
Speed of Sleigh,u=322 m/s
Speed of jet,u'=680 m/s
Mass of jet,m=4800 kg
Total mass=M+m=1200+4800=6000 kg
We have to find the final velocity of the two objects after the collision.
The collision is inelastic .
By using law of conservation of momentum
![Mu+mu'=(m+M)v](https://tex.z-dn.net/?f=Mu%2Bmu%27%3D%28m%2BM%29v)
Using the formula
![1200\times 322+4800\times 680=6000v](https://tex.z-dn.net/?f=1200%5Ctimes%20322%2B4800%5Ctimes%20680%3D6000v)
![6000v=3650400](https://tex.z-dn.net/?f=6000v%3D3650400)
![v=\frac{3650400}{6000}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B3650400%7D%7B6000%7D)
![v=608.4m/s](https://tex.z-dn.net/?f=v%3D608.4m%2Fs)
Hence, the final velocity of two objects after the collision=608.4m/s
The further the planet is from the sun the smaller the year is
Answer: C
produces as much as or more energy than it uses
Explanation:
This implies that the total energy used by the building is equivalent to the energy generated by the site
Heat energy: J
temp.: C or F (depends)