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3 years ago

A ball rolls at 3 meters per second. how much time does it take for the ball to roll 6 meters

Physics

2 answers:

natka813 [3]3 years ago

5 0

2 seconds skins b the answer

Rufina [12.5K]3 years ago

4 0

2 seconds
6meters/3meters=2

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4 years ago

A small charge q is placed near a large spherical charge Q. The force experienced by both charges is F. The electric eld created

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The electric field created by Q at the position of q is $\frac{F}{Q}$ .

The given parameters:

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Spherical charge, = Q
Force experienced by both charges, = F

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$E = \frac{F}{Q} \\\\$

where;

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3 years ago

You connect a 100-resistor, a 800-mH inductor, and a 10.0-uF capacitor in series across a 60.0-Hz, 120-V (peak) source. The impe

steposvetlana [31]

Answer:

Impedance, Z = 107 ohms

Explanation:

It is given that,

Resistance, R = 100 ohms

Inductance, $L=800\ mH=800\times 10^{-3}\ H=0.8\ H$

Capacitance, $C=10\ \mu F=10\times 10^{-6}\ F=10^{-5}\ F$

Frequency, f = 60 Hz

Voltage, V = 120 V

The impedance of the circuit is given by :

$Z=\sqrt{R^2+(X_C-X_L)^2}$ ...........(1)

Where

$X_C$ is the capacitive reactance, $X_C=\dfrac{1}{2\pi fC}$

$X_C=\dfrac{1}{2\pi \times 60\times 10^{-5}}=265.65\ \Omega$

$X_L$ is the inductive reactance, $X_L={2\pi fL}$

$X_L={2\pi \times 60\times 0.8}=301.59\ \Omega$

So, equation (1) becomes :

$Z=\sqrt{(100)^2+(265.65-301.59)^2}$

Z = 106.26 ohms

Z = 107 ohms

So, the impedance of the circuit is 107 ohms. Hence, this is the required solution.

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4 years ago