Which element is heavier lead or flourine
1 answer:
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Answer:
<h2>pH = 3.9</h2><h2>pOH = 10.1</h2>Explanation:
Since is a weak acid to find the pH of
we use the formula
where
Ka is the acid dissociation constant
c is the concentration
From the question
Ka of = 1.75 × 10^-5
c = 1.00 × 10-³M
Substitute the values into the above formula and solve for the pH
That's
We have the answer as
<h3>pH = 3.9</h3>To find the pOH we use the formula
pH + pOH = 14
pOH = 14 - pH
pOH = 14 - 3.9
We have the answer as
<h3>pOH = 10.1</h3>Hope this helps you
<h3>Answer:</h3>
2.0 mol C₆H₁₂O₆
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Step 1: Define</u>
1.2 × 10²⁴ molecules C₆H₁₂O₆ (glucose)
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:
- Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
1.99269 mol C₆H₁₂O₆ ≈ 2.0 mol C₆H₁₂O₆
