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alexira [117]
3 years ago
12

A sample of carbon monoxide gas has a volume of

Chemistry
1 answer:
jek_recluse [69]3 years ago
8 0

Answer: 2.3L

Explanation:

Given that:

Volume of carbon monoxide gas V1 = 3.45L

Temperature T1 = 28°C

Convert Celsius to Kelvin

(28°C + 273 = 301K)

Pressure P1 = 2.82 atm

Final Volume V2 = ?

Final temperature T2 = 28°C = 301K

Final pressure = 4.2atm

Then, apply the general gas equation

(P1V1)/T1 = (P2V2)/T2

(2.82 x 3.45)/301 = (4.2 x V2)/301

9.73/301 = 4.2V2/301

0.032 = 0.014V2

To get the value of V2, divide both sides by 0.014

0.032/0.014 = 0.014V2/0.014

2.286 = V2

Rounded to nearest tenth, V2 becomes 2.3L

Thus, the new volume of the carbon monoxide gas is 2.3 liters

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<u>Answer:</u> The mass of glucose in final solution is 1.085 grams

<u>Explanation:</u>

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M_1\text{ and }V_1 are the molarity and volume of the concentrated glucose solution

M_2\text{ and }V_2 are the molarity and volume of diluted glucose solution

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0.860\times 35.0=M_2\times 500\\\\M_2=\frac{0.860\times 35.0}{500}=0.0602M

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0.0602=\frac{\text{Mass of glucose solution}\times 1000}{180.2\times 100}\\\\\text{Mass of glucose solution}=\frac{0.0602\times 180.2\times 100}{1000}=1.085g

Hence, the mass of glucose in final solution is 1.085 grams

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