Answer: 2.3L
Explanation:
Given that:
Volume of carbon monoxide gas V1 = 3.45L
Temperature T1 = 28°C
Convert Celsius to Kelvin
(28°C + 273 = 301K)
Pressure P1 = 2.82 atm
Final Volume V2 = ?
Final temperature T2 = 28°C = 301K
Final pressure = 4.2atm
Then, apply the general gas equation
(P1V1)/T1 = (P2V2)/T2
(2.82 x 3.45)/301 = (4.2 x V2)/301
9.73/301 = 4.2V2/301
0.032 = 0.014V2
To get the value of V2, divide both sides by 0.014
0.032/0.014 = 0.014V2/0.014
2.286 = V2
Rounded to nearest tenth, V2 becomes 2.3L
Thus, the new volume of the carbon monoxide gas is 2.3 liters
