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Liula [17]
3 years ago
9

Which of the following is equal to 2.3 cm3?

Chemistry
1 answer:
Leya [2.2K]3 years ago
4 0
The answer is the second one 2.3 X 10-3 dm3
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How many molecules of carbon dioxide, CO2, are present in 388.1 grams?
swat32

Answer:

53.11× 10²³ molecules

Explanation:

Given data:

Number of molecules of CO₂ = ?

Mass of CO₂ = 388.1 g

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of CO₂ = 12× 1 + 16×2

Molar mass of CO₂ = 44 g/mol

Now we will put the values in formula.

Number of moles = 388.1 g/ 44 g/mol

Number of moles = 8.82 moles

Now we will calculate the number of molecules by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

8.82 mol × 6.022 × 10²³ molecules / 1 mol

53.11× 10²³ molecules

6 0
2 years ago
Suppose there was a release of 1 mole of Alpha emission particle and 1 mole of Beta emission particles and both particles are ac
Vitek1552 [10]

Answer:

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DT the best and they I'm on to work use as some help new thread so this communication contains you would appreciate everything about getting started using some new version from here or email the day car rental house has come home today was automatically and your company based website has anyone that a big hugs bhi to

DT the best and they I'm on to work use as some help new thread so this communication contains you would appreciate everything about getting started using some new version from here or email the day car rental house has come home today was automatically and your company based website has anyone that a big hugs bhi to

DT the best and they I'm on to work use as some help new thread so this communication contains you would appreciate everything about getting started using some new version from here or email the day car rental house has come home today was automatically and your company based website has anyone that a big hugs bhi to

Explanation:

DT the best and they I'm on to work use as some help new thread so this communication contains you would appreciate everything about getting started using some new version from here or email the day car rental house has come home today was automatically and your company based website has anyone that a big hugs bhi to

DT the best and they I'm on to work use as some help new thread so this communication contains you would appreciate everything about getting started using some new version from here or email the day car rental house has come home today was automatically and your company based website has anyone that a big hugs bhi to

DT the best and they I'm on to work use as some help new thread so this communication contains you would appreciate everything about getting started using some new version from here or email the day car rental house has come home today was automatically and your company based website has anyone that a big hugs bhi to

DT the best and they I'm on to work use as some help new thread so this communication contains you would appreciate everything about getting started using some new version from here or email the day car rental house has come home today was automatically and your company based website has anyone that a big hugs bhi to

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6 0
3 years ago
When calcium hydroxide is formed, heat is released. Calculate the amount of heat (in kJ) released when 2 moles of calcium hydrox
babunello [35]

Answer:

C

Explanation:

3 0
2 years ago
What is the percent of hydrogen by mass in CH4O
WITCHER [35]

Answer:

My guess would be  12.5828

4 0
3 years ago
The table shows the amount of radioactive element remaining in a sample over a period of time.
Assoli18 [71]

It would take 147 hours for 320 g of the sample to decay to 2.5 grams from the information provided.

Radioactivity refers to the decay of a nucleus leading to the spontaneous emission of radiation. The half life of a radioactive nucleus refers to the time required for the nucleus to decay to half of its initial amount.

Looking at the table, we can see that the initial mass of radioactive material present is 186 grams, within 21 hours, the radioactive substance decayed to half of its initial mass (93 g). Hence, the half life is 21 hours.

Using the formula;

k = 0.693/t1/2

k = 0.693/21 hours = 0.033 hr-1

Using;

N=Noe^-kt

N = mass of radioactive sample at time t

No = mass of radioactive sample initially present

k = decay constant

t = time taken

Substituting values;

2.5/320= e^- 0.033 t

0.0078 = e^- 0.033 t

ln (0.0078) = 0.033 t

t = ln (0.0078)/-0.033

t = 147 hours

Learn more: brainly.com/question/6111443

7 0
2 years ago
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