Use a periodic table, It should help
Answer:
7 to 4 (higher
)
5 to 3
3 to 2
4 to 2 (lower
)
Explanation:
We can use the Rydberg formula which relates the wavelength of the photon emissions to the principle quantum numbers involved in the transition:

with
final n, and
initial n
evaluating for each transition:
7 to 4 
5 to 3 
4 to 2 
3 to 2 
Note that the above formula is written for
, so lower
value obtained involves higher
.
So we should order from lower to higher 
7 to 4 (higher
)
5 to 3
3 to 2
4 to 2 (lower
)
Note: Take into account that longer wavelength involves lower energy (
).
Answer: Because sulfur is directly below oxygen in the periodic table, these elements have similar electron configurations. As a result, sulfur forms many compounds that are analogs of oxygen compounds, as shown in the table below. ... O=O. double bonds are much stronger than S=S double bonds.
Answer:
So fluorine and bromine are halogens and when you work out the Lewis dot structure you'll see that they each have one unpaired electron, therefore these unpaired electrons join together to form one bond.