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3 years ago

15

Lillianne made 6 out of every 10 baskets she attempted during basketball practice. If she attempted to make 25 baskets, how many

did she make

1 answer:

patriot [66]3 years ago

3 0

Answer:

15.

Step-by-step explanation:

(6/ 10) * 25

= 0.6 * 25

= 15.

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Hey and I supposed to add or multiple when there is volume?

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Answer:

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Step-by-step explanation:

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The function h is given by h ( t ) = ( 1 − t ) ( 8 + 16 t ) models the height of a ball in feet, t seconds after it is thrown.

Elena-2011 [213]

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Answer:

zeros: t = 1, t = -1/2
no: the domain of the function is t ≥ 0
8 feet

Step-by-step explanation:

The zeros are the values of t that make the factors zero.

1 -t = 0 ⇒ t = 1

8 +16t = 0 ⇒ t = -8/16 = -1/2

The equation is used to model height after the ball is thrown. We don't expect it to be a good model before the ball is thrown (t < 0), so the zero in that region is extraneous.

Only the positive zero is in the function's domain, so that is the only one that is meaningful.

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When t = 0 (at the time the ball is thrown), the function value is ...

h(0) = (1 -0)(8 +0) = 8

The ball is thrown from a height of 8 feet.

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3 years ago

A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find th

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F(t) = (t^-1) - t
Taking derivative:
<span>f'(t) = d/dt(t^-1) - t) = d/dt(t^-1) - d/dt(t) </span>
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2 years ago

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The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the proba

zlopas [31]

Answer:

The probability that there are 8 occurrences in ten minutes is

option B. 0 .0771

Step-by-step explanation:

Given:

Random Variable = x

Mean number of occurrences in ten minutes is 5.3.

The probability of an occurrence is the same in any two time periods of an equal length

To Find:

The probability that there are 8 occurrences in ten minutes = ?

Solution:

Let X be the number of occurrences of the event X

$X \sim {Pois} (\lambda)$

$\lambda = E(X) = 5.3$

Possion of distribution is given by ,

$P(X=x) = \frac{e^{- \lambda} \lambda^{x}}{x!}$

Substituting the values,

$P(X=8) = \frac{e^{- 5.3} 5.3^{8}}{8!}$

$P(X=8) = \frac{(0.004994) ( 622596.904)}{40320}$

$P(X=8) = \frac{(3109.24894)}{40320}$

P(X=8) = 0.0771

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3 years ago