1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
guajiro [1.7K]
2 years ago
14

Determine, in correct order, the correct number of protons, neutrons and electrons.

Chemistry
1 answer:
erastovalidia [21]2 years ago
5 0

Answer:

for example magnesium is atomic number 12 it has 12 protons and 12 electrons

Explanation:

You might be interested in
A rocky hill cracks after water settles and freezes. Several trees on the hill tilt due to the very slow downhill movement of ro
Marat540 [252]

Answer:

A. Creep

Explanation:

Creep is usually defined as a mass movement process where the rock and other particles are forced to move slowly downward along a slope that is mostly covered with softer sediments and broken rock fragments. It results in the tilting of trees, poles, and gravestones.

5 0
3 years ago
Read 2 more answers
What is a dynamic process?
Deffense [45]

The correct answer is D

7 0
4 years ago
For a reaction A + B → products, the following data were collected. Experiment Number Initial Concentration of A (M) Initial Con
Afina-wow [57]

Answer:

Rate constant k = 1.57*10⁻⁵ s⁻¹

Explanation:

Given reaction:

A\rightarrow B

Expt    [A] M        [B] M         Rate [M/s]

1          3.40         4.16           1.82*10^-4

2         4.59         4.16           3.32*10^-4

3.        3.40          5.46          1.82*10^-4

Rate = k[A]^{x}[B]^{y}

where k = rate constant

x and y are the orders wrt to A and B

To find x:

Divide rate of expt 2 by expt 1

\frac{3.32*10^{-4} }{1.82*10^{-4} } =\frac{[4.59]^{x} [4.16]^{y} }{[3.40]^{x} [4.16]^{y} }\\\\x =2

To find y:

Divide rate of expt 3 by expt 1

\frac{1.82*10^{-4} }{1.82*10^{-4} } =\frac{[3.40]^{x} [5.46]^{y} }{[3.40]^{x} [4.16]^{y} }\\\\y =0

Therefore: x = 2, y = 0

Rate = k[A]^{2}[B]^{0}

To find k

Use rate for expt 1:

k = \frac{Rate1}{[A]^{2} } =\frac{1.82*10^{-4}M/s }{[3.40]^{2} } =1.57*10^{-5} s-1

6 0
3 years ago
A small car with mass = 800 kg slows from 15 m/s to 10 m/s. What is the
iVinArrow [24]

Answer:b

Explanation:

3 0
3 years ago
How can I balance chemical equations by providing the correct coefficients? For example: [?]Pb(NO3)2 + [?]NaCrO4 = [?]PbCrO4 + [
melomori [17]

Answer:

Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + 2NaNO₃

The coefficients are: 1, 1, 1, 2

Explanation:

Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + NaNO₃

The above equation can be balance as follow:

Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + NaNO₃

There are 2 atoms of Na on the left side and 1 atom on the right side. It can be balance by writing 2 before NaNO₃ as shown below:

Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + 2NaNO₃

Now the equation is balanced.

The coefficients are: 1, 1, 1, 2

3 0
3 years ago
Other questions:
  • If 2.03 g of oxygen react with carbon monoxide, how many grams of CO2 are formed?
    11·1 answer
  • How would the boiling point of a cup of water compare to the boiling point of two gallons of water?
    13·2 answers
  • Part A The reaction A(aq)⇌2B(aq) is performed at two different temperatures and the equilibrium constant determined. At temperat
    6·1 answer
  • Witch of these is not a biomass energy source
    14·1 answer
  • An unknown metal cation (alias, M) contains 26 total electrons. It forms an ionic compound
    11·1 answer
  • How is an atom's atomic mass number determined? How is an atom's atomic mass number determined? The atomic mass number is determ
    10·1 answer
  • In the following description of Fe, some of the properties are physical and some are chemical. Identify which of the properties
    6·1 answer
  • Phosphorus reacts with aqueous sodium hydroxide as in the equation below:
    5·1 answer
  • Shape of the periodic table
    15·1 answer
  • How would you prepare a 1 L solution of 3 M MgO?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!