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frez [133]
3 years ago
7

How would you prepare a 1 L solution of 3 M MgO?

Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:  175.35g

Explanation:  A 3 M solution has 3 moles of solute per litre.

The mass of one mole of NaCl equals the MW of NaCl MW =  35.45 + 23 =58.45 g/mol

The mass of 3 moles is 58.45 g/mol ×3 mol=175.35 g NaCl  or  200 g rounded to one sigfig.

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Answer:

The correct answer is - sulfur.

Explanation:

In the periodic table, there are 18 groups and 7 rows or periods arranged according to their atomic number or electronic configuration. In the question, it is mentioned that the desired element atomic mass is less than the atomic mass of the selenium which is 78.96, and more than oxygen which is 15.99 with 6 electron valence and present in the third row.

As it has 6 valency of electron it must be in the 16 group of the table that comprises the 6 valency and as it is located in the 3rd row it must be sulfur that also has an atomic mass between selenium and oxygen.

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What type of solid is this? This solid has high melting point, does not conduct electricity, and does not dissolve in water. Met
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3 years ago
there is a total of seventeen constitutional isomers for the molecular formula c5h13n. draw the skeletal formula of all three co
MAXImum [283]
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Secondary Amines:
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Tertiary Amines:
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3 years ago
What does 3.5 degree of unsaturation tell you?
Kaylis [27]

Answer:

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While alkynes have 3 bonds, it must be understood that they have 2 pi bonds only and as such their degree of saturation is two.

In the case of an alkene, there is only one single pi bond and as such the degree of unsaturation is 1.

Now in this case, we have a fractional 0.5 degree of unsaturation alongside the 3 to make a total of 3.5. So what’s the issue here?

The fractional part shows that the chemical entity we are dealing with here is a radical. While the integer 3 shows that there are 3 pi-bonds, the half pi bond remaining tells us that there is a missing electron on one of the atoms involved in the chemical bonding and as such, the 1/2 extra degree of unsaturation tends to tell us this.

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