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Nitella [24]
2 years ago
13

How can I balance chemical equations by providing the correct coefficients? For example: [?]Pb(NO3)2 + [?]NaCrO4 = [?]PbCrO4 + [

?]NaNO3
Chemistry
1 answer:
melomori [17]2 years ago
3 0

Answer:

Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + 2NaNO₃

The coefficients are: 1, 1, 1, 2

Explanation:

Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + NaNO₃

The above equation can be balance as follow:

Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + NaNO₃

There are 2 atoms of Na on the left side and 1 atom on the right side. It can be balance by writing 2 before NaNO₃ as shown below:

Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + 2NaNO₃

Now the equation is balanced.

The coefficients are: 1, 1, 1, 2

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what does it mean when the h3o+ to x- distance doesn't change much as the first 4 to 5 water molecules are added
podryga [215]
If X is an equivalent base to H₂O
HX is an equivalent acid to H₃O⁺
HX is a stronger acid than H₃O⁺
HX is not an acid
X⁻ is a stronger base than H₂O
HX is a weaker acid than H₃O⁺
X⁻ is a weaker base than H₂O
X⁻ is not a base.

The correct response or this is 
X⁻ is a stronger base than H₂O
HX is a weaker acid than H₃O⁺
7 0
3 years ago
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What is the mass, in grams, 200mL of liquid with a density of 1.4g/mL
Tcecarenko [31]

The mass of the liquid is 280 g.

Mass = 200 mL × (1.4 g/1 mL) = 280 g

6 0
3 years ago
Mention two substance that sublines​
Ugo [173]

Familiar substances that sublime readily include iodine , dry ice , menthol, and camphor. Sublimation is occasionally used in the laboratory as a method for purification of solids, for example, with caffeine.

8 0
2 years ago
why are experimental investigations the best type of scientific investigation to demonstrate cause and effect relationships
Lelu [443]
Because they are coming from the ground and always safe
8 0
3 years ago
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TRIPLE POINTS!!! I NEED HELP!!! PLEASE EXPLAIN TOO!!! What is the energy of a quantum of light with a frequency of 4.31 x 1014 1
Lelechka [254]

Answer:

The answer is

2.86 \times  {10}^{ - 19}  \: J

Explanation:

The energy of a quantum of light can be found by using the formula

<h3>E = hf</h3>

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 4.31 × 10¹⁴ Hz

We have

E = 4.31 × 10¹⁴ × 6.626 × 10-³⁴

We have the final answer as

2.86 \times  {10}^{ - 19}  \: J

Hope this helps you

3 0
3 years ago
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