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REY [17]
3 years ago
15

What is a dynamic process?

Chemistry
1 answer:
Deffense [45]3 years ago
7 0

The correct answer is D

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Which of the following conditions remain constant in Gay-Lussac's law? Temperature and number of moles Volume and number of mole
saw5 [17]

Answer:

Volume and number of moles.

Explanation:

  • Gay-Lussac's law was found by Joseph Louis Gay-Lussac in 1808.
  • It states that, for a given mass (no. of moles) and constant volume of an ideal gas, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.

So, no. of moles and V are constant.

P ∝ T,

<em>∴ P1/T1 = P2/T2.</em>

  • So, the right choice is: <em>Volume and number of moles.</em>
3 0
3 years ago
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On the calendar, the full moon is shown happening on the eleventh of the month. What moon would you see around the date shown wi
Elan Coil [88]

Answer: waning gibbous

Explanation:

Your welcome

7 0
3 years ago
What is potential energy?
Vlad [161]

Answer:

B

Explanation:

it is the energy stored in the chemical bonds of a substance

4 0
2 years ago
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What are the limitations of Bronsted-Lowery concept???
HACTEHA [7]

Answer:

There is no limitation at all because that is the basic theory of solution electrolysis

3 0
4 years ago
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A sheet of gold weighing 8.8 g and at a temperature of 10.5°C is placed flat on a sheet of iron weighing 19.5 g and at a tempera
timofeeve [1]

Answer:

T = 36.393\,^{\textdegree}C

Explanation:

The contact between the sheet of gold and the sheet of iron allows a heat transfer until thermal equilibrium is done, which means that both sheets have the same temperature:

-Q_{iron} = Q_{gold}

-(0.008\,kg)\cdot (452\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-54.4\,^{\textdegree}C) = (0.0195\,kg)\cdot (129\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-10.5\,^{\textdegree}C)

-(3.616\,\frac{J}{^{\textdegree}C})\cdot (T-54.4\,^{\textdegree}C) = (2.515\,\frac{J}{^{\textdegree}C})\cdot (T-10.5^{\textdegree}C)

-1.438\cdot (T - 54.4^{\textdegree}C) = T-10.5^{\textdegree}C

-1.438\cdot T +78.227^{\textdegree}C = T - 10.5^{\textdegree}C

2.438\cdot T = 88.727\,^{\textdegree}C

The final temperature is:

T = 36.393\,^{\textdegree}C

8 0
3 years ago
Read 2 more answers
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