Half the length of the curve which separates the 2 halves = 1/2 circumference of a circle with diameter 6 mm. = 1/2 * pi * d = 3pi mm
So the length of the line = 6pi = 18.85 mm to nearest hundredth. answer
The area of shaded region = 1/2 area of the circle = 1/2 pi r^2
= 1/2 * pi * 6^2
= 56.55 mm^2 to nearest hundredth answer
Answer:
(x - 2)/3
(x - 4)/-5 or (-x + 4)/5
Step-by-step explanation:
this is an inverse function, and to solve an inverse function you would :
swap x and g(x) without bringing the x coefficient with it, just simply swap the variables. Then, solve for g(x), and that's it
the first question's answer is :
g(x) = 3x + 2
x = 3(g(x)) + 2
x - 2 = 3(g(x))
(x - 2)/3 = g(x)
the second one is:
g(x) = 4 - 5x
x = 4 - 5(g(x))
x - 4 = -5(g(x))
(x-4)/-5 = g(x)
Answer:
Step-by-step explanation:
As you can see from the graph I attached you, the possible solutions in the interval from 0 to 2π are approximately:

So, it's useful to solve the equation too, in order to verify the result:

Taking the inverse sine of both sides:

Using this result we can conclude the solutions in the interval from 0 to 2π are approximately:

Step-by-step explanation:
1st way: 5x
2nd way: 5.x
third way: 5(x)
Answer:
Nice art work, dear
Step-by-step explanation:
Good job
Stay safe, stay healthy and blessed.
Have a nice day !
Thank you