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yuradex [85]
3 years ago
6

2CuS + 3O2 = 2CuO + 2SO2

Chemistry
1 answer:
Nata [24]3 years ago
4 0
I have no yuuuuu to say anything abt to
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Gas is heated from 480. K to 750. K and the pressure is kept constant, what final volume would result if the original volume was
attashe74 [19]
Charles law gives the relationship between volume and temperature of gas.
It states that at constant pressure volume is directly proportional to temperature
Therefore
V/ T = k
Where V - volume T - temperature in kelvin and k - constant
V1/T1 = V2/T2
Parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
Substituting the values in the equation
267 L/ 480 K = V / 750 K
V = 417 L
Final volume is 417 L
8 0
3 years ago
Each step in the following process has a yield of 90.0 %. CH 4 + 4 Cl 2 ⟶ CCl 4 + 4 HCl CCl 4 + 2 HF ⟶ CCl 2 F 2 + 2 HCl The CCl
Rainbow [258]

Answer:

4.86 moles of HCl

Explanation:

1. First write the balanced chemical equations involved in the process:

CH_{4}+_4Cl_{2}=CCl_{4}+_4HCl

CCl_{4}+_2HF=CCl_{2}+F_{2}+_2HCl

2. Calculate what amount of CCl_{4} is formed in the first reaction.

3.00molesCH_{4}*\frac{1molCCl_{4}}{1molCH_{4}}=3.00molesCCl_{4}

As the yield of each reaction is 90.0%, the amount of CCl_{4} produced is the following:

3.00molesCCl_{4}*0.90=2.7molesCCl_{4}

3. Calculate the amount of HCl produced.

2.7molesCCl_{4}*\frac{2molHCl}{1molCCl_{4}}=5.4molesHCl

The total amount of HCl produced with a 90.0% yield is:

5.4molesHCl*0.90=4.86molesHCl

4 0
3 years ago
Convert 25 km to mm.
nalin [4]

Answer:

25000000 millimeters

Explanation:

4 0
3 years ago
Read 2 more answers
Consider the following incomplete reaction. Mg + 2Y ---> MgCl₂ + H₂ Choose the formula for the missing substance Y.
Feliz [49]
It would be:
B. HCl

A metal will react with an acid to form a salt (MgCl2) and H2.
8 0
3 years ago
A 13.5 g sample of an unknown gas occupies 5.10 L at 149.83 kPa and 301 K. What is the molar mass of the gas ?
alisha [4.7K]

Answer:

The molar mass of the gas is 44.19 g/mol

Explanation:

Amount of sample of gas = m = 13.5 g

Volume occupied by the gas = V = 5.10 L

Pressure of the gas = P = 149.83 KPa

1 KPa = 0.00986 atm

P = 149.83 \textrm{ KPa} \times 0.00986 \textrm{ atm/KPa} = 1.48 \textrm{ atm}

Assuming M g/mol to be the molar mass of the gas

Assuming the gas is behaving as an ideal gas

\textrm{PV} =\textrm{nRT} \\\textrm{PV} = \displaystyle \frac{m}{M}\textrm{ RT } \\1.48 \textrm{ atm}\times 5.10 \textrm{ L} = \displaystyle \frac{13.5 \textrm{ g}}{M}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 301\textrm{K} \\M = 44.19 \textrm{ g/mol}

The molar mass of gas is 44.19 g/mol

7 0
4 years ago
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