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2 years ago

Identify the oxidizing and reducing agents in this reaction: Cr2O3(s) + 2Al(s) 2Cr(s) + Al2O3(s)

Chemistry

2 answers:

DiKsa [7]2 years ago

7 0

In this reaction, Cr2O3 is the oxidizing agent which will oxidize Al to Al2O3.

Al is the reducing agent that will reduce Cr2O3 to Cr.

An oxidizing agent has the property of oxidizing another molecule (giving it one or more oxygen atoms) by being reduced.

A reducing agent has the property of reducing another molecule (by removing one or more oxygen molecules) by being oxidized.

aivan3 [116]2 years ago

3 0

Cr2O3+ 2Al -----------> 2Cr+ Al2O3

Cr2O3--------2Cr.
( oxidation no. of cr +3 to +1 means hain of electron so it act as oxidizing agent)

similarly,

2Al------> Al2O3
( oxidation no. of Al +1 to +3 means loss of electron so it act as reducing agent)

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How do valence electrons interact between non polar covalent, polar covalent, and ionic bonds?

iVinArrow [24]

Answer:

In non-polar covalent bonds, the electrons are equally shared between the two atoms. For atoms with differing electronegativity, the bond will be a polar covalent interaction, where the electrons will not be shared equally.

Explanation:

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2 years ago

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katrin2010 [14]

Answers:

Question 1:

The diagram for gallium will have flat, horizontal lines at 30 and 2204 °C.

Questoin 2:

The diagram for methane will have a diagonal line representing the liquid phase between -183°C and -162°C.

Question 3:

For gold, the boiling point corresponds to the y-value at 2856 °C of the top horizontal line

Question 4.

For nitrogen, the line at -210°C will be flat, which represents the change from a solid to a liquid

Explanations:

Question 1:

The diagram for gallium will have flat, horizontal lines at 30 and 2204 °C.

The table shows that the melting point of gallium is 30°C and its boiling point is 2204°C.

Melting point is the temperature at which the substace changes its state from solid to liquid. During that change, the temperature of the substance does not change, because the heat supplied is used to accomplish the phase change. So, the temperature is constant and that means that portion of the diagram is flat.

The same is valid during boiling: the temperature remains constant while the substance is passing from liquid to gas at the boiling point.

Questoin 2:

The diagram for methane will have a diagonal line representing the liquid phase between -183°C and -162°C.

Between the melting (-183°C) and boiling (-162°C) points of methane, its temperature will increase more or less linearly, which is represented with a diagonal (slant) line between those points. During this interval the heat is used to increase the temperature and no phase of change happens.

Question 3:

For gold, the boiling point corresponds to the y-value at 2856 °C of the top horizontal line

The table shows that the boiling point of gold is 2,856°C.

In a temperature-vs.-time diagram the temperature is represented on the vertical axis (y-value) and the time is represented on the horizontal axis.

Since, the temperature of the substance does not change during boiling, the line during the time that this change of phase is happening is flat. And since this temperatue is higher than the melting temperature, this is the top horizontal line in the diagram.

Question 4.

For nitrogen, the line at -210°C will be flat, which represents the change from a solid to a liquid

The table shows that the melting point of nitrogen is -210°C, that means that the temperature will remain constant at -210°C while the substance is absorbing heat to pass from solid to liquid.

In conclusion, you must remember that all the phase changes, melting (from solid to liquid), freezing (from liquid to solid), boilng (from liquid to gas), and condensing (from gas to liquid) happens at constant temperature, and so the temperature - vs. - time diagrams show flat lines (constant y-values) during those intervals of time.

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2 years ago

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What's the answer to equation Ba+Br2=

Andrej [43]

Answer:

BaBr2, Barium Bromide

Explanation:

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3 years ago

a mixture consisting of only of lithium chloride, lithium carbonate, and lithium nitrate was analyzed

Dafna11 [192]

A mixture consisting of only of lithium chloride, lithium carbonate, and lithium nitrate was analyzed by the help of concentric hydrochloric acid.

<h3>What is concentric hydrochloric acid?</h3>

The concentric hydrochloric acid is used for the analysis of organic and inorganic mixture like lithium chloride, lithium carbonate, and lithium nitrate it releases fumes and cannot be touched with normal hands.

Always use a dropper to use it and for the chemical analysis.

Therefore, mixture consisting of only of lithium chloride, lithium carbonate, and lithium nitrate was analyzed by the help of concentric hydrochloric acid.

Learn more about concentric hydrochloric acid, here,

brainly.com/question/24586675

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1 year ago

Ammonia NH3 percentage composition

Firlakuza [10]

Answer:

82.24% percent composition of N and 17.76% percent composition of H .

Explanation:

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2 years ago