Answer:
10.5 dm3 O2
0.94 moles de MgO
Explanation:
La pregunta dice explícitamente que el magnesio es puro en un 90%.
Por lo tanto, masa de magnesio puro = 90/100 * 25G = 22,5 g
Número de moles de Mg = 22,5g / 24g/mol = 0,94 moles de Mg
La ecuación de reacción es;
2Mg (s) + O2 (g) ------> 2MgO (s)
Si 2 moles de Mg reaccionan con 1 moles de O2
0.94 moles de Mg reacciona con 0.94 * 1/2 = 0.47 moles de O2
Si 1 mol de O2 ocupa 22,4 dm3
0.47 moles de O2 ocupan 0.47 * 22.4 / 1 = 10.5 dm3
También;
2 moles de Mg producen 2 moles de MgO
Entonces, 0.94 moles de Mg producen 0.94 moles de MgO
Answer:
because it's water chemical bonds form when atoms share electrons and example of a chemical compound is water a water molecule forms when oxygen and hydrogen atoms react and are held together by covalent bonds like other compounds water always has the same chemical composition a ratio of two one of hydrogen atoms to oxygen atoms
To solve this we assume that the gas is an ideal gas.
Then, we can use the ideal gas equation which is expressed as PV = nRT. At a
constant volume and number of moles of the gas the ratio of T and P is
equal to some constant. At another set of condition, the constant is still the
same. Calculations are as follows:
T1/P1 = T2/P2
P2 = T2 x P1 / T1
P2 = 293 x 748 / 525
<span>P2 = 417.46 kPa</span>
