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Goryan [66]
3 years ago
5

If it requires 18.2 mL of 0.45 molar barium hydroxide to neutralize 38.5 mL of nitric acid, solve for the molarity of the nitric

acid solution. Show all the work used to solve this problem
Chemistry
1 answer:
krok68 [10]3 years ago
4 0

The moles of OH- ions from the Ba(OH)2 must equal the moles of H+ ions from the HNO3 in order for them to neutralize. You must multiply volume (in liters) by the molar to get number of moles. There is 0.90 molar of OH- because there is twice as many OH- as there is Ba(OH)2. The molarity of H+ is unknown.

Let X be the unknown molarity


(0.0182 L)(0.90 M) = (0.0385 L)(X M)

X = 0.43 M (2 significant figures)


So the molarity of H+ ions, and therefore HNO3 is 0.43 M

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B. compound
source is Glencoe Science book grade 7.
Also I just happening to be learning about this at school
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3 years ago
Why is acylation reagent important.
shepuryov [24]

Answer:

<em>Acylation can be used to prevent rearrangement reactions that would normally occur in alkylation. </em>

3 0
2 years ago
A new grill has a mass of 30.0 kg. you put 1.5 kg of charcoal in the grill. you burn all the charcoal and the grill has a mass o
atroni [7]

The reaction for burning of charcoal or complete combustion is as follows:

C(s)+O_{2}(g)\rightarrow CO_{2}(g)

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Molar mass of pure carbon is 12 g/mol thus,

n=\frac{1.5\times 10^{3} g}{12 g/mol}=125mol

The same moles of CO_{2} is released. Converting these moles into mass as follows:

m=n×M

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7 0
3 years ago
Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction entropy of the following chemical rea
Aleksandr [31]

Answer:

ΔS° = - 47.2 J/mol.K

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5 0
3 years ago
Read 2 more answers
Please help!!
Olegator [25]
Molarity =  Moles/Liter

Use the molecular atomic mass of NaCl to convert from grams to moles.
Molecular mass of NaCl is the sum of its atomic masses. Look at the periodic table to find these. Na is 23 g/mol and Cl is 35.5 g/mol ,
so NaCl = 23 + 35.5 = 58.5 g/mol

multiply to cancel out grams
76 g NaCl * (1mol / 58.5 g NaCl) = 1.3 mol NaCl

over 1 Liter is just 1.3 M NaCl
Hope this helps!
8 0
3 years ago
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