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Molodets [167]
3 years ago
9

A pure gold ring with a volume of 1.79 cm^3 is initially at 17.4 ∘C. When it is put on, it warms to 28.5 ∘C. How much heat did t

he ring absorb? (density of gold =19.3 g/cm^3)
Chemistry
1 answer:
yKpoI14uk [10]3 years ago
6 0

Answer:

Hi Adriana!. You should need to find out which is the specific heat for gold. As this value is 0.129 J/g °C.  The ring has absorbed 49.5 J of heat.

Explanation:

First of all, you have to use the density formula to find out your mass.

d = mass/volume

19.3 g/cm3 = mass / 1.79 cm3

19.3 g/cm3 x 1.79 cm3 = mass

34.55 g = mass

Now, that we have the gold mass, let's go to the specific heat formula

Heat = mass . Specific heat . ΔT (where ΔT means the difference between temperatures.- Tfinal - Tinitial) So..

Heat = mass . Specific heat . ΔT

Heat = 34.55 g x 0.129 J/g °C x (28.5°C - 17.4°C)

Heat = 34.55 g x 0.129 J/g °C x (11.1°C)

Heat = 49.5 J

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Which element will be more reactive - Mg (magnesium) OR Se (Selenium)? *
anygoal [31]

Answer:

magnesium

Explanation:

magnesium is in Group 2, in the periodic table. this means that it has 2 valence electrons. the less valence electrons an element or atom has, the more reactive. Selenium has 6 valence electrons. as a result, Mg is more reactive

5 0
3 years ago
If I have 6 moles of a gas at a pressure of 3.4 atm and a volume of 10 liters, what
ch4aika [34]

Answer:

The temperature is 69.05 K.  

Explanation:

We have,

Number of moles are 6

Pressure is 3.4 atm and a volume of 10 liters.

It is required to find the temperature. It can be calculated using gas law equation. It says that,

PV=nRT

P is pressure

V is volume

n is number of moles

R is gas constant, R=0.082057\ L-atm/mol-K

T is temperature                

Plugging all the values we get :

T=\dfrac{PV}{nR}\\\\T=\dfrac{3.4\times 10}{6\times 0.082057}\\\\T=69.05\ K

So, the temperature is 69.05 K.  

8 0
3 years ago
Neils Bohr published his model of the atomic structure in 1913. He introduced the theory of electrons traveling in orbits around
Effectus [21]

Answer:

The number of atoms in the outermost shell  

Explanation:

For example, the electron shells in the alkali metals contain the following numbers of electrons:

 Li: 2, 1

Na: 2, 8, 1

 K: 2, 8, 8, 1

They all have one electron in their outermost shell, and they have similar chemical properties.

4 0
3 years ago
At 150°C the decomposition of acetaldehyde CH3CHO to methane is a first order reaction. If the
Crank

The decomposition time : 7.69 min ≈ 7.7 min

<h3>Further explanation</h3>

Given

rate constant : 0.029/min

a concentration of  0.050 mol L  to a concentration of 0.040 mol L

Required

the decomposition time

Solution

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time

For first-order reaction :

[A]=[Ao]e^(-kt)

or

ln[A]=-kt+ln(A0)

Input the value :

ln(0.040)=-(0.029)t+ln(0.050)

-3.219 = -0.029t -2.996

-0.223 =-0.029t

t=7.69 minutes

4 0
2 years ago
Will give brainlsit need answers asap!
k0ka [10]

Answer:

120 g of NaCl in 300 g H20   at 90 C

Explanation:

At x = 90   go vertical to the line for NaCl...then go left to the y-axis to find the solubility in 100 g H20   = 40

we want   300 g H20    so multiply this by  3    to get   120 gm of NaCl in 300 g

7 0
2 years ago
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