Ask question

Ask question

All categories

3 years ago

11

calculate the amount of current that must flow for 50 minutes to a solution of silver trioxonitrate (V) solution to deposit 2 mo

le of silver. (Ag=108, Faraday's constant=96500C mol¯¹)

1 answer:

mamaluj [8]3 years ago

5 0

Explanation:

i found this the question is different but I think the situation is same

You might be interested in

What is the best description of cirrus clouds?

miskamm [114]

Option 1

Explanation:

Cirrus clouds are short, detached, hair-like clouds found at high altitudes

6 0

2 years ago

Read 2 more answers

Zeke is on spring break. He lives in a cold climate, so he decides to drive to a warmer climate. Before he leaves for his vacati

STatiana [176]

The warmer temperatures at Zeke's destination caused the volume of air in his tires to increase.

4 0

3 years ago

Read 2 more answers

Calculate the freezing point of a solution made from 220g of octane (C Hua), molar mass = 114,0 gmol dissolved in 1480 g of benz

stiv31 [10]

Answer: Freezing point of a solution will be $-1.16^0C$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(5.50-T_f)^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant = $5.12^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (benzene)= 1480 g =1.48 kg

Molar mass of solute (octane) = 114.0 g/mol

Mass of solute (octane) = 220 g

$(5.50-T_f)^0C=1\times 5.12\times \frac{220g}{114.0 g/mol\times 1.48kg}$

$(5.50-T_f)^0C=6.68$

$T_f=-1.16^0C$

Thus the freezing point of a solution will be $-1.16^0C$

3 0

3 years ago

The length breadth and thickness of a brick is 18cm 8 cm and 5cm respictively find the area of the widest part of rhe brick

Sunny_sXe [5.5K]

Answer:

144cm²

Explanation:

Given dimensions:

Length x breadth x thickness

18cm x 8cm x 5cm

The widest part of this figure will be the face containing the length and the breadth.

The breadth is the width of the figure;

Area of the widest part = length x breadth = 18cm x 8cm = 144cm

The area of the widest part of the figure is 144cm²

4 0

3 years ago

A student is riding his bicycle the 4 km to school from his house. The graph

masya89 [10]

Answer:

Explanation:

ポイントをありがとう

4 0

3 years ago