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Dmitriy789 [7]
3 years ago
11

calculate the amount of current that must flow for 50 minutes to a solution of silver trioxonitrate (V) solution to deposit 2 mo

le of silver. (Ag=108, Faraday's constant=96500C mol¯¹)​
Chemistry
1 answer:
mamaluj [8]3 years ago
5 0

Explanation:

i found this the question is different but I think the situation is same

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How many grams are in 1 mole of Pb3(PO4)4?
kvasek [131]

Answer:

In 1 mol of Pb₃(PO₄)₄ occupies 1001.48 grams

Explanation:

This compound is the lead (IV) phosphate.

Grams that occupy 1 mole, means the molar mass of the compound

Pb = 207.2  .3 = 621.6 g/m

P = 30.97 .4 = 123.88 g/m

O = (16 .  4) . 4 = 256 g/m

621.6 g/m + 123.88 g/m + 256 g/m = 1001.48 g/m

6 0
3 years ago
Read 2 more answers
Find a mole of 0.0960 g of H2SO4
nignag [31]
Molar mass H₂SO₄ = 98.079 g/mol

1 mol -------- 98.079 g
? mole ------ 0.0960 g

moles = 0.0960 * 1 / 98.079

= 0.0960 / 98.079

= 9.788 x 10⁻⁴ moles

hope this helps!
3 0
3 years ago
What is the limiting reactant for the following balanced equation when 9 moles of AlF3 are mixed with 12 miles of O2?
tamaranim1 [39]
<h2>Answer:AlF_{3} </h2>

Explanation:

The chemical equation of the reaction that occurs when AlF_{3} reacts with O_{2} is

4AlF_{3}+3O_{2}→2Al_{2}O_{3}+6F_{2}

4 moles of AlF_{3} requires 3 moles of O_{2}.

1 mole of AlF_{3} requires \frac{3}{4} moles of O_{2}.

Given that we have 9 moles of AlF_{3}.

9 moles of AlF_{3} requires \frac{3}{4}\times 9=6.75 moles of O_{2}.

But we have 12 moles of O_{2}.

So,AlF_{3}  will be consumed first.

So,AlF_{3}  is the limiting reagent.

3 0
3 years ago
Are these two substances the same 1.96g/ml and 2.00g/ml
Zolol [24]

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Explanation:

4 0
3 years ago
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How do you slow down the motion of a gas particle?
jasenka [17]
I think u turn down the heat not to sure
3 0
3 years ago
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