On a straight horizontal track along which blocks can slide with negligible friction, block 1 slides toward block 2, which is in
1 answer:
If the mass and post-collision speed of block 1 is known, the momentum of the block 2 can be determined.
<h3>What is momentum?</h3>The momentum of an object in motion is the product of mass and speed of the object.
P = mv
<h3>Conservation of linear momentum</h3>The principle of conservation of linear momentum states that, the sum of the initial momentum must be equal to the sum of the final momentum.
Thus, if the mass and post-collision speed of block 1 is known, the momentum of the block 2 can be determined.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
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Answer:
12.7 N
15.7 N
Explanation:
mass (m) = 0.15 kg
radius (r) = 0.6 m
speed = 2 rps = 2 x 60 = 120 rpm
acceleration due to gravity (g) = 9.8 m/s^{2}
find the tension at the top and bottom of the circle.
Tension at the top T =
- where v = speed in m/s
v = radius x rpm x 0.10472 = 0.6 x 120 x 0.10472 = 7.54 m/s
- we can now substitute the value of v into T =
T = = 12.7 N
Tension at the bottom T' =
- where v = speed in m/s
v = radius x rpm x 0.10472 = 0.6 x 120 x 0.10472 = 7.54 m/s
- we can now substitute the value of v into T' =
T' = = 15.7 N
Answer:
time at which Kathy overtakes Stan is 6.70 sec
Explanation:
given data
time = 1 sec
acceleration= 3.4 m/s²
acceleration = 4.49 m/s²
to find out
the time at which Kathy overtakes Stan
solution
we consider here travel time for kathy = t1
and travel time for stan is = t2
and we know initial velocity = 0
so
t1 = 1 + t2
and distance travel equation by kinematic is
d1 = ut + at²
d1 = 0+ 4.49 (t2)² ................1
and
d2 = 0 + 3.4 (1+t2)² ..................2
and when overtake distance same so from equation 1 and 2
4.49 (t2)² =
3.4 (1+t2)²
t2 = 6.703828 sec
so time at which Kathy overtakes Stan is 6.70 sec